无法从意图onActivityResult获取文件uri [英] Can't get file uri from intent onActivityResult

问题描述

我想从 onActivityResult 接收正常的文件路径，如下所示:

I would like to receive normal file path from onActivityResult like this:

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
        super.onActivityResult(requestCode, resultCode, data)
        if (resultCode == RESULT_OK) {
            Log.i("m", data!!.dataString!!)
            convertFileToString(data.dataString!!)

        }
    }

但是我收到这样的错误:

but I receive such error:

java.io.FileNotFoundException: File 'content:/com.android.providers.media.documents/document/image%3A18' does not exist

此异常来自将我的文件转换为字符串的方法.此错误指向此行:

this exception comes from method which converts my file to string. This error points to this line:

try {
val data = FileUtils.readFileToByteArray(file) // this line

} catch (e: IOException) {
e.printStackTrace()
}

此文件也存在，但我无法获取.我在这里看到了一些问题，这些问题建议获取像这样的 REAL 路径:

This file exists also but I can't get it. I saw here some questions which suggest to get REAL path like this:

fun getPath(context:Context, uri:Uri):String {
  val result:String = null
  val proj = arrayOf<String>(MediaStore.Images.Media.DATA)
  val cursor = context.getContentResolver().query(uri, proj, null, null, null)
  if (cursor != null)
  {
    if (cursor.moveToFirst())
    {
      val column_index = cursor.getColumnIndexOrThrow(proj[0])
      result = cursor.getString(column_index)
    }
    cursor.close()
  }
  if (result == null)
  {
    result = "Not found"
  }
  return result
}

但是此方法返回此类异常:

but this method return such exception:

java.io.FileNotFoundException: File 'Not found' does not exist

所以，我在这里收到的 data !!.dataString !! :

So, what I receive here data!!.dataString!!:

content://com.android.providers.media.documents/document/image%3A18

以及我在这里收到的内容 Log.i("m"，uri.path.toString()):

and what I receive here Log.i("m",uri.path.toString()):

/document/image:18

我看到这不是保存该图形的真实路径.也许有人知道我在哪里出错?)

as I see this is not real path on which this pict was saved. Maybe someone knows where I made errors?)

我如何将文件转换为字符串:

How I convert file to string:

fun convertFileToString(path: String) {
        //dialog.dismiss()
        val file = File(path)

        for (i in 0 until sn.array!!.size()) {
            val jsonObj = sn.array!![i].asJsonObject
            val nFile = jsonObj.get("filename").asString

            if (file.name == nFile) {
                Toast.makeText(this, R.string.message_about_attached__file, Toast.LENGTH_SHORT).show()
                return
            }
        }

        try {
            val data = FileUtils.readFileToByteArray(file)
            uploadFiles(File(path).name, Base64.encodeToString(data, Base64.NO_WRAP))
        } catch (e: IOException) {
            e.printStackTrace()
        }
    }

推荐答案

我想从onActivityResult接收正常的文件路径，如下所示:

I would like to receive normal file path from onActivityResult like this:

我的猜测是您使用的是 ACTION_OPEN_DOCUMENT ，或者也许是 ACTION_GET_CONTENT .您将得到一个 content Uri ，这正是这些 Intent 操作被记录返回的内容.这样的 Uri 可能有以下支持:

My guess is that you are using ACTION_OPEN_DOCUMENT, or perhaps ACTION_GET_CONTENT. You are getting a content Uri, which is exactly what those Intent actions are documented to return. Such a Uri might be backed by:

• 外部存储上的本地文件，您可能无法在Android 10+上访问
• 内部存储中另一个应用程序的本地文件
• 可移动存储中的本地文件
• 已加密且需要动态解密的本地文件
• 数据库的 BLOB 列中保存的字节流
• 互联网上的内容首先需要由其他应用下载
• 动态生成的内容
• ...等等

此异常来自将我的文件转换为字符串的方法

this exception comes from method which converts my file to string

我假设通过将我的文件转换为字符串"，是指以 String 的形式读取文件内容.在这种情况下:

I assume that by "converts my file to string", you mean read the file contents in as a String. In that case:

通过在 Context (例如您的 Activity getContentResolver()来
• 获取 ContentResolver >
• 在 ContentResolver 上调用 openInputStream()，传入您的 Uri ，在 Uri
标识的内容
• 在 InputStream 上调用 reader().readText()以获取表示文件内容的 String

• Get a ContentResolver by calling getContentResolver() on a Context, such as your Activity
• Call openInputStream() on the ContentResolver, passing in your Uri, to get an InputStream on the content identified by the Uri
• Call reader().readText() on the InputStream to get a String representing the file contents

结合起来，应该像这样:

Combined, that should be something like:

val string = data.data?.let { contentResolver.openInputStream(it).use { it.reader().readText() } }

这篇关于无法从意图onActivityResult获取文件uri的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！