来自Apache返回退出code -6与不stdout或stderr子进程 [英] subprocesses from apache returning exit code -6 with not stdout or stderr

问题描述

当从Apache进程中运行混帐地位，甚至LS，我会经常得不到标准输出或错误，以及-6退出状态code。其他时候，它只是工作。任何想法，为什么这是发生或意味着什么？

When running "git status" or even "ls" from an apache process, I will frequently get no standard output or error, and an exit status code of -6. Other times, it just works. Any ideas why this is occurring or what it means?

推荐答案

如果你是一个很多人在网络上，你可能会耗尽可用的并发连接。这是假设你是在Linux上，当你谈论你的遥控器。 10个并发安全的集合默认值是不够的，如果你通过SSH有很多的并发连接。

If you are on a network with a lot of people, you may be running out of available concurrent connections. This assumes you are on Linux when you talk about your remote. The default of 10 concurrent secure collections is not enough if you have lots of simultaneous connections via ssh.

这是混帐运行在本地机器上解释，然后需要访问远程的多个文件以获得什么是在指数和当前提交的树中的图片。

This is explained by git running on your local machine and then needing to access multiple files on the remote to get the picture of what is in the index and the current commit's tree.

这篇关于来自Apache返回退出code -6与不stdout或stderr子进程的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！