意图ACTION_SEND不会显示每个浏览器 [英] Intent ACTION_SEND doesn't show every browser

问题描述

我有一个按钮，当点击以下按钮时，该按钮会触发ACTION_SEND意图:

I have a button which fires a ACTION_SEND intent when clicked as below:

private static final String WEB_URL = "https://www.google.ca/";

@Override
public void onClick(View v) {
    Intent intent = new Intent();
    intent.setAction(Intent.ACTION_SEND);
    intent.putExtra(Intent.EXTRA_TEXT, WEB_URL);
    intent.setType("text/plain");
    startActivity(Intent.createChooser(intent, "CHOOOOOSE"));
}

当前，它具有一些其他应用程序，复制到剪贴板"和添加到Firefox"，可用于在Firefox中打开链接.但是，我想让用户决定要使用哪个浏览器应用程序打开链接，但是当我正在使用的该设备同时具有"Chrome"和"Internet"应用程序时，添加到Firefox"似乎是唯一的选择

Currently, it has some other apps, 'Copy to clipboard', and 'Add to Firefox' which can be used to open the link in Firefox. However, I want to let a user to decide which browser app to use to open the link but 'Add to Firefox' seems to be the only option right now when this device I am using has 'Chrome' and 'Internet' applications as well.

最终，我想要的是一个共享按钮，并且在单击事件中，它显示所有已安装的浏览器应用程序，例如chrome，firefox，互联网"等，复制到剪贴板"以及任何其他应用程序(<-这些不是必需的.)

Ultimately, what I want is a share button, and on a click event, it shows all installed browser app like chrome, firefox, 'internet', etc., 'Copy to clipboard', and any other apps(<- these are not necessary, though).

显示所有浏览器应用和按钮"复制到剪贴板"是我的本质要求.

Showing all browser apps, and a button to 'Copy to clipboard' is what I essentially want.

"WEB_URL"字符串始终是正确的网址.

The 'WEB_URL' string is always going to be a proper url.

我该如何实现?

编辑

总结:

我希望有一个由"Intent.createChooser()"显示的应用程序列表，该列表包含所有浏览器应用程序和复制到剪贴板"选项.

I want to have a list of apps shown by 'Intent.createChooser()' whose list consist of ALL browser apps AND a 'Copy to clipboard' option.

我尝试将Intent.ACTION_VIEW与intent.setData(Uri.parse(url))一起使用，但是在这种情况下，它没有复制到剪贴板"选项.

I tried using Intent.ACTION_VIEW with intent.setData(Uri.parse(url)) but then in this case, it doesn't have the 'Copy to clipboard' option.

推荐答案

解决方案

经过研究，我能够达到我想要的目标.

I was able to achieve what I wanted above after some research.

关键是使用"Intent.EXTRA_INITIAL_INTENTS"和自定义活动.

The key is to use 'Intent.EXTRA_INITIAL_INTENTS' and a custom Activity.

SomeActivity的onClick事件

private static final String WEB_URL = "https://www.google.ca/";

@Override
public void onClick(View v) {
    Intent intent = new Intent();
    intent.setAction(Intent.ACTION_VIEW);
    intent.setData(Uri.parse(WEB_URL));

    Intent clipboardIntent = new Intent(SomeActivity.this, CopyToClipboardActivity.class);
    clipboardIntent.setData(Uri.parse(WEB_URL));

    Intent chooserIntent = Intent.createChooser(intent, "Custom Title...");
    chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, new Intent[] {clipboardIntent});
    startActivity(chooserIntent);
}

将"CopyToClipboardActivity"添加到清单

<activity android:name=".activities.CopyToClipboardActivity"
    android:exported="false"
    android:icon="@drawable/someIcon"
    android:label="@string/copy_to_clipboard"
    android:theme="@android:style/Theme.NoDisplay"/>

CopyToClipboardActivity.java

public class CopyToClipboardActivity extends Activity {
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        Uri uri = getIntent().getData();
        if (uri != null) {
            copyTextToClipboard(uri.toString());
            Toast.makeText(this, "Link copied to clipboard", Toast.LENGTH_SHORT).show();
        }

        // Finish right away. We don't want to actually display a UI.
        finish();
    }

    private void copyTextToClipboard(String url) {
        ClipboardManager clipboard = (ClipboardManager) getSystemService(Context.CLIPBOARD_SERVICE);
        ClipData clip = ClipData.newPlainText("URL", url);
        clipboard.setPrimaryClip(clip);
    }
}

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