如何确定Android设备的最小宽度 [英] How to determine smallest width of android device

问题描述

我是与不同屏幕尺寸相关联的android布局概念的新手.我希望为8的标签页制作不同的布局，并将其放置在"layout-swxxxx"文件夹中.对于大于8"的标签页，请在"layout"文件夹中使用另一种通用布局.

I am new to the concepts of android layouts associated with different screen sizes. I wish to make a different layout for a tab which is of 8" and place it in a "layout-swxxxx" folder. And have another generic layout for tabs bigger than than 8" in "layout" folder.

这是我的8英寸平板电脑的配置.屏幕尺寸8.0英寸分辨率1200 x 1920像素(〜283 ppi像素密度)

Here is the configuration of my 8" tablet. Screen size 8.0 inches Resolution 1200 x 1920 pixels (~283 ppi pixel density)

谁能告诉我如何计算"sw"，以便我可以相应地命名布局文件夹.

Can anyone tell me how to calculate the "sw", so that i can name my layout folder accordingly.

我也没有物理设备，因此我不可能用任何代码来找到该值.因此，请请求其他方法.

Also I don't have the physical device with me so its not possible for me to find this value with any code. So request an alternative method.

谢谢.

推荐答案

链接dp，像素和密度的公式如下:

The formula linking dp, pixels and density is as follow :

px = dp *(dpi/160)

px = dp * (dpi / 160)

因此，就您而言，

widthInDp = widthInPx / (dpi / 160)
widthInDp = 1200 / (283 / 160)
widthInDp = ~678dp

因此，您将要使用sw600dp之类的存储桶

So you're gonna want to use a bucket such as sw600dp

参考文献: http://developer.android.com/guide/practices/screens_support.html

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