试图建立Apache和Django的在一起的时候空白页 [英] Blank page when trying to set up Apache and Django together
问题描述
我试图建立Python和Django的与Apache的共同努力。
I'm trying to set up Python and Django to work together with Apache.
Django的项目给我的只是一个空白页,所以我尝试了样品,我在很多地方找到:
The Django project gave me nothing but a blank page, so I've tried a sample I've found in many places:
def application(environ, start_response):
status = '200 OK'
output = 'This is my Website!'
response_headers = [('Content-type', 'text/plain'),
('Content-Length', str(len(output)))]
start_response(status, response_headers)
return [output]
我在我的app.py文件的开头添加以下行:
I've added the following lines at the beginning of my app.py file:
#!C:/Program Files/Python34/python.exe
print('Content-Type: text/html')
print('\n\n')
我仍然得到一个空白页。
I still get a blank page.
如果我添加以下code:
If I add the following code:
def testFunction(text):
print(text)
testFunction('this works')
我得到适当的输出('这工作'),所以我想我的Python脚本的是的运行。但是,我怎么得到调用应用程序(ENVIRON,start_response)被称为?
I get the appropriate output ('this works') so I guess my Python script is running. But how do I get the callable application(environ, start_response) to be called ?
我很新到Python / Django和有些新的Apache的,所以我可能会丢失一些小事,但这里是我试过:
I'm very new to Python/Django and somewhat new to Apache so I may be missing something trivial, but here's what I've tried:
- 展望Apache日志文件,但没有什么在error.log中(即使我已经设置loglevel改为'信息')
- 确保没有其他模块可以干扰(不mod_php的或mod_python的加载)
- 添加WSGIApplicationGroup%{} GLOBAL
- 不使用任何虚拟主机或VIRTUALENV保持它的简单
- 在文件和文件夹权限检查(所有已阅读和放大器;执行检查)
下面是我的Apache的配置文件的部分:
Here is the section of my Apache config file:
WSGIScriptAlias /wsgi "C:/PythonWorkspace/app.py"
<Directory "C:/PythonWorkspace">
Options ExecCGI
AddHandler cgi-script .cgi .py
Require all granted
</Directory>
配置为:在Windows Server 2008 / Apache的2.4瓦特的mod_wsgi / Python的3.4 / 1.6.5 Django的
Config is: Windows Server 2008 / Apache 2.4 w MOD_WSGI / Python 3.4 / Django 1.6.5
预先感谢任何指针!
推荐答案
这code是用于 CGI
print('Content-Type: text/html')
print('\n\n')
print('This is my Website!')
这是code是用于 WSGI
def application(environ, start_response):
status = '200 OK'
output = 'This is my Website!'
response_headers = [('Content-type', 'text/plain'),
('Content-Length', str(len(output)))]
start_response(status, response_headers)
return [output]
Apache的配置为使用 CGI
为的.py
文件
AddHandler cgi-script .cgi .py
要使用 WSGI
需要
AddHandler cgi-script .cgi # removed .py
AddHandler wsgi-script .py
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