仅从ansible剧本中运行一个任务和处理程序 [英] Run only one task and handler from ansible playbook

问题描述

我如何从Ansible剧本中运行单个任务，以及如何在该任务成功完成时获得通知的处理程序，同时跳过相关剧本中的所有其他任务?

How can I run a single task from an Ansible playbook and the handler that gets notified when that task completes successfully, while skipping all other tasks in the relevant playbook?

当前，我执行以下操作:

Currently I execute the following:

ansible-playbook --start-at-task "task1" --step -K -i hosts playbook.yml

，然后在任务完成后按 Ctrl + c .但是，这也会跳过处理程序.

and then press Ctrl+c after the task has finished. This will also skip the handler however.

我知道我可以在任务中添加标签并使用它，如

I know I can add a tag to the task and use that, as in How to run only one task in ansible playbook?, but I would prefer being able to do this without adding a tag. Is that possible?

推荐答案

ansible-playbook目前没有任何东西可以让您运行单个任务，例如-task .因此，对我来说，标记和-tags 选项一起是您的最佳解决方案.

There's currently nothing coming with ansible-playbook to allow you to run a single task, like --task. Thus, to me, the tag along with the --tags option is your best solution here.

这篇关于仅从ansible剧本中运行一个任务和处理程序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！