Spark:创建一个嵌套模式 [英] Spark: create a nested schema
本文介绍了Spark:创建一个嵌套模式的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
有火花,
import spark.implicits._
val data = Seq(
(1, ("value11", "value12")),
(2, ("value21", "value22")),
(3, ("value31", "value32"))
)
val df = data.toDF("id", "v1")
df.printSchema()
结果如下:
root
|-- id: integer (nullable = false)
|-- v1: struct (nullable = true)
| |-- _1: string (nullable = true)
| |-- _2: string (nullable = true)
现在,如果我想自己创建模式,应该如何处理?
Now if I want to create the schema myself, how should I process?
val schema = StructType(Array(
StructField("id", IntegerType),
StructField("nested", ???)
))
谢谢.
推荐答案
根据此处的示例: https://spark.apache.org/docs/2.4.0/api/java/org/apache/spark/sql/types/StructType.html
import org.apache.spark.sql._
import org.apache.spark.sql.types._
val innerStruct =
StructType(
StructField("f1", IntegerType, true) ::
StructField("f2", LongType, false) ::
StructField("f3", BooleanType, false) :: Nil)
val struct = StructType(
StructField("a", innerStruct, true) :: Nil)
// Create a Row with the schema defined by struct
val row = Row(Row(1, 2, true))
根据您的情况,它将是:
And in your case it will be:
import org.apache.spark.sql._
import org.apache.spark.sql.types._
val schema = StructType(Array(
StructField("id", IntegerType),
StructField("nested", StructType(Array(
StructField("value1", StringType),
StructField("value2", StringType)
)))
))
输出:
StructType(
StructField(id,IntegerType,true),
StructField(nested,StructType(
StructField(value1,StringType,true),
StructField(value2,StringType,true)
),true)
)
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