如何在线索中将相关案例和字段从一种记录类型更新为另一种记录类型 [英] How to update related cases and fields from one recordtype to other recordtype in lead

问题描述

public class UpdaterecordtypeforLead {
    Public static void Leadtootherupdate() {
     List<Lead> OlderLead = [SELECT Id,Name, RecordTypeId from Lead where RecordType.Name = 'Enquiries'];
    List<Lead> NewLead = New List<Lead> ();
    If(NewLead.Id == null)
    {
       for( Lead l : OlderLead) {
          for(Lead l1 : NewLead) {
               l1.LastName = l.LastName;
               l1.Email= l.Email;
               NewLead.add(l1);
               NewLead.add(l1);
              Insert l1;
          }
       }
    
    If ( (l1. LastName == l.LastName && l1.Email == l.Email)) 
    {
          NewLead.add(OlderLead.Related_Cases__c);
          NewLead.add(l.Id);
          Update NewLead;
   }
} 
     
    }
}
     

保存时出现错误.

推荐答案

我认为您有很多问题:

• 此代码的上下文/目的是什么?
• 使用 DeveloperName 而不是 Name 进行查询，因为它取决于语言
• 在列表中测试 if(NewLead.Id == null)无效
• 出于什么原因而选择NewLead?
• 重复 NewLead.add(l1)
• 插入循环将使您达到调速器限制，应避免使用此方法进行批量插入
• if 是否在循环之外
• 不要更新您刚刚插入的内容，而是请确保在插入之前一切正常
• NewLead 是 Lead 的列表，因此您不能添加 OlderLead.Related_Cases__c 或 l.Id
• 考虑正确缩进代码，其他人更容易阅读
• 使用命名约定

• What is the context / aim of this code ?
• Query using DeveloperName not Name as it's language dependent
• Testing if (NewLead.Id == null) when ``NewLead` is a list will not work
• Looping on NewLead for what reason ?
• Duplicate NewLead.add(l1)
• Insert in a loop will gets you to governor limits and should be avoided, go for bulk insert
• The if is outside the loop
• Don't update something you just insert, instead make sure everything is okay before insert
• NewLead is a list of Lead so you can't add OlderLead.Related_Cases__c or l.Id to it
• Think about indenting correctly your code, it's easier for others to read
• Use naming conventions

固定代码可能是这样的:

A fixed code would probably be something like this:

public class UpdateRecordtypeForLead {
    public static void leadToOtherUpdate () {
        List<Lead> olderLeads = [
            SELECT 
                Id,
                LastName,
                Email,
                RecordTypeId
            FROM 
                Lead 
            WHERE 
                RecordType.DeveloperName = 'Enquiries'
        ];
        List<Lead> newLeads = New List<Lead>();

        for (Lead olderLead : olderLeads) {
            newLeads.add(new Lead(
                Id = olderLead.Id,
                LastName = olderLead.LastName,
                Email = olderLead.Email,
                RecordTypeId = 'the_new_record_type_id'
            ));
          }
       }

       update newLeads;
   }
}

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