在Arduino上使用串行软件发送3个浮点变量 [英] Sending 3 float variables with serial software on Arduino

问题描述

我正在尝试使用软件串行库通过带有Arduino的无线模块发送机器人的位置.我发现它一次只能发送1个字节.我发送的号码不能超过255，我需要发送彩信直到40000.我该怎么做?

I'm trying to send position of my robot through wireless module with Arduino using Software Serial library. I found that it can only send 1 byte at time. I can't send more than number 255 and I need to send floats till 40000. How I can do that?

这是我的发射器的一个示例:

Here is an example of my transmitter:

#include <SoftwareSerial.h>
SoftwareSerial mySerial(10, 11); // RX, TX

void setup()
{
// Open serial communications and wait for port to open:
Serial.begin(9600);
mySerial.begin(9600);
}

void loop() // run over and over    
{       
  float i=40000;
mySerial.write(i);
  //Serial.println(i);}    
}

我的收信人

#include <SoftwareSerial.h>
SoftwareSerial mySerial(10,11); // RX, TX
int i=0;
void setup()
{
// Open serial communications and wait for port to open:
Serial.begin(9600);
mySerial.begin(9600);    
}

void loop() {
if(mySerial.available()){
  i=mySerial.read();
Serial.println(i);    
}
}

推荐答案

您必须使用 Serial.println(floatVal); 将其以纯文本格式发送，并带有任何空格分隔符，并通过 Serial.parseFloat()方法.

You have to use Serial.println(floatVal); to send it in plain text with any white space separator and receive it by Serial.parseFloat() method.

write 方法非常适合发送原始数据(单个字符，c字符串或某些缓冲区)

The write method is good for sending raw data (single character, c-string or some buffer)

如果您真的想以二进制形式发送浮点数，则必须将其作为缓冲区传递: Serial.write((uint8_t *)& floatVal，sizeof(intVal)); .在接收器端，您还必须阅读整个浮动. read()方法仅读取一个字符.

If you really want sending floats in its binary form, you have to pass it as an buffer: Serial.write((uint8_t*)&floatVal, sizeof(intVal));. And on the receiver side you have to read whole float too. The read() method reads only one character.

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