未定义指数：用户名在C：\\ XAMPP \\ htdocs中\\ HMS \\ login.php中上线927 [英] Undefined index: username in C:\xampp\htdocs\hms\login.php on line 927

问题描述

我有问题登录并销毁会话创建。的反馈是：

I am having problem login out and destroying session created. the feed back are:

Notice: Undefined index: username in C:\xampp\htdocs\hms\login.php on line 927


Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\hms\login.php:241) in C:\xampp\htdocs\hms\login.php on line 927


Notice: Undefined variable: _SESSION in C:\xampp\htdocs\hms\login.php on line 928


Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\hms\login.php:241) in C:\xampp\htdocs\hms\login.php on line 929

在这些行引用的code是
241线至275：

The referenced code in those line are Line 241 to 275:

<?php
require("include/dbinfo.php");
$link=mysql_connect($server,$user,$pass)or die(errorReport(mysql_error()));
mysql_select_db($db,$link)or die(errorReport(mysql_error()));
if(!isset($_GET['pid']))
{
    echo "<div><link rel=\"stylesheet\" href=\"css/style01.css\">";
    $username=$_COOKIE['username'];
    $sessionid=$_COOKIE['PHPSESSID'];
    $row=mysql_query("select * from session where username='$username' and id='$sessionid'");
    if(!empty($row)&&(mysql_num_rows($row)))
    {
        $result=mysql_query("select * from employee where Employee_ID='$username'");
        if($row=mysql_fetch_array($result))
        {
            $name=$row['Name'];
            $eid=$row['Employee_ID'];
            $dept=$row['Dept_No'];
            $gender=$row['Gender'];
            $contact=$row['Contact'];
            $dob=$row['DOB'];
            $add=$row['Address'];
            echo "<h3>Personal Details</h3>";
            echo "<table border=0 cellpadding=1 cellspacing=0 style=\"margin:5px 0px 0px -3px;\">";
            echo "<tr><td width=5%>Name: </td><td width=50%>$name</td></tr>";
            echo "<tr><td>Employee ID: </td><td>$eid</td></tr>";
            echo "<tr><td>Date of Birth: </td><td>$dob</td></tr>";
            echo "<tr><td>Department: </td><td>$dept</td></tr>";
            echo "<tr><td>Contact: </td><td>$contact</td></tr>";
            echo "<tr><td>Gender: </td><td>$gender</td></tr>";
            echo "<tr><td>Address: </td><td>$add</td></tr>";
            echo "</table>";
        }
    }
    echo "</div>";

920线至931：

Line 920 to 931:

else if(isset($_GET['pid'])&&(strcmp($_GET['pid'],"logout")==0))
{
    $username=$_COOKIE['username'];
    $sessionid=$_COOKIE['PHPSESSID'];
    if(mysql_query("select * from session where username='$username' and id='$sessionid'"))
    {
        $result=mysql_query("delete from session where username='$username'and id='$sessionid'");
        setcookie("username",$_POST['username'],time()-3600);
        unset($_SESSION['PHPSESSID']);
        header('Location: index.php');
    }
    echo "</div>";

请，这里有什么问题？

推荐答案

您没有设置未设置（$ _ SESSION ['PHPSESSID']）; ，但你不要有在session_start（）来启动它。请把它放在℃后，右上角; PHP 标记。
因为你没有张贴用户名价值，但其在cookie中，你把它定义为 $用户名，更改此

You unset unset($_SESSION['PHPSESSID']); but you dont have session_start() to start it. Please put it at the top right after the <?php tags. Because you are not posting the username value but its in the cookie, and you defined it as $username, Change this

setcookie("username",$_POST['username'],time()-3600);

要

setcookie("username",$username,time()-3600);

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