指向C中数组的指针 [英] Pointer to Array in C

问题描述

您如何解释以下代码行?

How can you interpret the following line of code?

int (*arrayABC)[10];

在我的教科书中，它说我们有一个指向整数数组第0个元素的指针.

In my textbook, it says that we have a pointer to a pointer to the 0th element of an integer array.

但是，我对此不太了解.

However, I don't quite understand this.

我的解释:我们有一些变量，它的值是某个地址.然后，该地址是UNNAMED整数数组的第0个元素的地址.基本上，我们有一个指向第0个元素的指针.

My interpretation: We have some variable, which gets as its value some address. This address is then the address of the 0th element of an UNNAMED integer array. Basically we have a pointer to the 0th element.

那为什么要有指向POINTER的指针呢?

Why then to have a pointer TO A POINTER?

推荐答案

这是指向数组的指针.它不是指向指针的指针.数组和指针是不同的.数组具有一个地址，但数组不是一个地址.数组是一系列连续的元素.

This is a pointer to an array. It is not a pointer to a pointer. Arrays and pointers are different. An array has an address, but an array is not an address. An array is a series of contiguous elements.

此指针不仅指向第一个元素，还指向整个数组，而 float * 指向整个浮点，而不仅仅是第一个字节.

This pointer points to the whole array and not just the first element, in the same way that a float * points to the whole float and not just the first byte.

例如，如果您有:

int foo[10];
int (*arrayABC)[10] = &foo;

然后，表达式(* arrayABC)和 foo 是相同的.例如. foo [3] 与(* arrayABC)[3] 相同.

then the expressions (*arrayABC) and foo are identical. E.g. foo[3] is the same as (*arrayABC)[3].

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