查找子数组的总和 [英] Finding the sum of subarrays
本文介绍了查找子数组的总和的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在处理一个非常大的子数组数组,这些子数组的数字我想将每个子数组减少为一个总和.
I'm working on a very large array of subarrays full of numbers that I want to reduce into one sum for each subarray.
示例:
var arr = [[1,2,3], [4,5,6]];
arr.forEach(function(item) {
item.reduce(function(a, b) {
return a + b;
});
});
console.log(arr);
//I want arr to equal [[6], [15]];
我的解决方案只是返回原始数组元素
My solution just returns the original array element
推荐答案
尝试如下操作:
var arr = [[1,2,3], [4,5,6]];
var newArr = [];
arr.forEach(function(item) {
item = item.reduce(function(a, b) {
return a + b;
});
newArr.push([item]);
});
console.log(newArr);
为简洁起见,您可以使用传递给forEach回调的值:当前正在迭代的项目,该项目的索引以及数组本身:
To be a bit more concise, you can use the values passed to the forEach callback: the item you're currently iterating through, the index of that item, and the array itself:
arr.forEach(function(item, index, array) {
array[index] = [array[index].reduce(function (a, b) {
return a + b;
})];
});
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