Javascript:按三个值对对象数组进行排序 [英] Javascript: sorting an array of objects by three values

问题描述

我有一个对象数组，我想使用.sort()函数进行排序.它应按三个值排序(第一个按第一个值排序，然后按第二个按值排序，最后按第三个按值排序).我已经尝试过类似以下的方法，但是它似乎无法正常工作.

  myArray.sort(function(a，b){如果(a.Value1 === b.Value1){如果(a.Value2 === b.Value2){返回(a.Value3< b.Value3)吗?-1:(a.Value3> b.Value3)?1:0；} 别的 {返回(a.Value2< b.Value2)吗?-1:1;}} 别的 {如果(a.Value2 === b.Value2){return(a.Value1< b.Value1)吗?-1:1;} 别的 {返回(a.Value2< b.Value2)吗?-1:1;}}}); 

任何帮助将不胜感激.

解决方案

这通常很好，但是在 a.Value1！== b.Value1 的琐碎情况下，您搞砸了逻辑./p>

这是固定版本:

  myArray.sort(function(a，b){如果(a.Value1 === b.Value1){如果(a.Value2 === b.Value2){返回(a.Value3< b.Value3)吗?-1:(a.Value3> b.Value3)?1:0；} 别的 {返回(a.Value2< b.Value2)吗?-1:1;}} 别的 {返回(a.Value1< b.Value1)吗?-1:1;}}); 

演示

I have an array of objects that I would like to sort using the .sort() function. It shall be sorted by three values (first by the first value, then by the second and finally by the third). I have tried something like the following but it doesn't seem to work properly.

myArray.sort(function(a,b) {
     if (a.Value1 === b.Value1) {
         if (a.Value2 === b.Value2) {
             return (a.Value3 < b.Value3) ? -1 : (a.Value3 > b.Value3) ? 1 : 0;
         } else {
             return (a.Value2 < b.Value2) ? -1 : 1;
         }
     } else {
         if (a.Value2 === b.Value2) {
             return(a.Value1 < b.Value1) ? -1 : 1;
         } else {
             return (a.Value2 < b.Value2) ? -1 : 1;
         }
     }
 });

Any help will be appreciated.

解决方案

It was mostly good but you messed up the logic in the trivial case where a.Value1 !== b.Value1.

Here's a fixed version :

myArray.sort(function(a,b) {
     if (a.Value1 === b.Value1) {
         if (a.Value2 === b.Value2) {
             return (a.Value3 < b.Value3) ? -1 : (a.Value3 > b.Value3) ? 1 : 0;
         } else {
             return (a.Value2 < b.Value2) ? -1 : 1;
         }
     } else {
          return (a.Value1 < b.Value1) ? -1 : 1;
     }
});

Demonstration

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