TypeError:尝试更改数组列表的某些元素时，列表索引必须是整数，而不是元组 [英] TypeError: list indices must be integers, not tuple when trying to alter certain elements of a list of arrays

问题描述

我有一个x和y坐标的2×n数组的列表.

I have a list of 2 by n arrays of x and y coordinates.

old: [array([[1, 2, 3], [4, 5, 6]]), array([[10, 20, 30], [40, 50, 60]])]

我正在尝试将y坐标(每个数组的第二行)移动某个值'shift'.但是，当我尝试通过以下方法执行此操作时，出现错误:

I am trying to shift the y-coordinates, the second row of each array, by a certain value 'shift'. However, when I try to do this by the method below, I get the an error:

"TypeError:尝试更改数组列表的某些元素时，列表索引必须是整数，而不是元组."

"TypeError: list indices must be integers, not tuple when trying to alter certain elements of a list of arrays."

import pylab


    def shiftY(old,shift):
        new = list([])

        for i in arange(len(old)):
            y = old[i][1,:] + shift
            newItem = array([old[:,0],y])
            new.append(newItem)

        return new

    old = list()
    old.append(arr

ay([[1, 2, 3], [4, 5, 6]]))
old.append(array([[10,20,30],[40,50,60]]))
shift =3 
new=shiftY(old,shift)
print(new)

跟踪:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python27_32bit\lib\site-packages\spyderlib\widgets\externalshell\sitecustomize.py", line 540, in runfile
    execfile(filename, namespace)
  File "C:/Users/tald574/testShifty.py", line 25, in <module>
    new=shiftY(old,shift)
  File "C:/Users/tald574/testShifty.py", line 15, in shiftY
    newItem = array([old[:,0],y])
TypeError: list indices must be integers, not tuple

我看不到我在做错什么，因为 newItem 甚至都不应该是列表，它应该是2D数组.如果有人可以告诉我我做错了什么以及如何解决它，将不胜感激.

I can't see what I am doing wrong as newItem is not even supposed to be a list, it should be a 2D array. Would appreciate it if someone can tell me what I do wrong an how to fix it.

谢谢.

该测试的预期结果将是

new:[array([[1, 2, 3], [7, 8, 9]]), array([[10, 20, 30], [43, 53, 63]])]

推荐答案

列表切片表示法中不需要逗号. array [:，i] 被解析为 array [:t] ，其中 t =，i 是一个元组.有关列表切片的摘要，请参见此处.

You don't need the commas in the list slicing notation. array[:,i] is parsed as array[:t], where t = ,i is a tuple. See here for a rundown of list slicing.

组是由以下定义逗号，而不是括号.

根据您的情况，替换行

y = old[i][1,:] + shift
newItem = array([old[:,0],y])

使用

y = old[i][1:] + shift
newItem = array([old[:0],y])

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