数组中最小的数字及其位置 [英] Smallest number in array and its position

问题描述

我要实现的目标是找到数组中最小的数字及其初始位置.这是一个示例，它应该做什么:

What I am trying to achieve is to find smallest number in array and its initial position. Here's an example what it should do:

temp = new Array();
temp[0] = 43;
temp[1] = 3;
temp[2] = 23;

所以最后我应该知道数字3和位置1.在这里我也看了一眼:

So in the end I should know number 3 and position 1. I also had a look here: Obtain smallest value from array in Javascript?, but this way does not give me a number position in the array. Any tips, or code snippets are appreciated.

推荐答案

仅循环遍历数组并查找最低编号:

Just loop through the array and look for the lowest number:

var index = 0;
var value = temp[0];
for (var i = 1; i < temp.length; i++) {
  if (temp[i] < value) {
    value = temp[i];
    index = i;
  }
}

现在 value 包含最小值，而 index 包含在数组中存在此类值的最低索引.

Now value contains the lowest value, and index contains the lowest index where there is such a value in the array.

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