从Java编写的C#中读取字节数组 [英] read byte array from C# that is written from Java

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本文介绍了从Java编写的C#中读取字节数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试从C#编写一个Integer并从Java读取它.两种语言的整数均为4字节.但是,当我从C#编写时,以下字节中写入了整数11000.表示第一个字节为1,其余为0.

I am trying to write an Integer from C# and read it from Java. An integer is 4 bytes in both languages. However when I write it from C#, integer 1 is written in the following bytes 1000. Meaning the first byte is 1 and the rest is 0.

但是在Java中,相同的东西写为0001.测量的前3个字节为0,最后一个为1.

But in Java the same thing is written as 0001. Meaing the first 3 bytes are 0 and the last is 1.

在这些语言之间是否有一种简单的读写方法,而不是手动反转每个4字节?Java代码

Is there a simple way of reading and writing among these languages instead of manually reversing every 4 byte? The code for Java

ByteBuffer buffer = ByteBuffer.allocate(4);
buffer.putInt(1);

for(byte b: buffer.array()){
      System.out.print(b);
}

C#的代码

MemoryStream ms = new MemoryStream();
using(BinaryWriter writer = new BinaryWriter(ms))
{
    writer.Write((int)1);

}
foreach(byte b in ms.ToArray()){
    Console.Write(b);
}

推荐答案

此帖子指向aus

As this post points aus http://kirkwylie.blogspot.com/2008/11/c-binarywriter-is-little-endian-because.html C# BinaryWriter supports only little endian so you have to configure it on the java site with the order method http://download.oracle.com/javase/1.4.2/docs/api/java/nio/ByteBuffer.html#order%28java.nio.ByteOrder%29

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