JavaScript:如何对包含NaN的数组进行排序 [英] JavaScript: How do you sort an array that includes NaN's

问题描述

我正在尝试对有时具有 Infinity 或 NaN 的数组进行排序.当我使用标准的JavaScript array.sort()时，似乎会进行排序，直到达到 NaN ，然后我得到随机结果.

  var数组= [.02，.2，-.2，Nan，Infinity，20]; 

有没有办法对此进行排序，以使最终结果从负数到正数，并且最后仍具有 NaN 或 Infinity .

 -.2，.02，.2,20，NaN，Infinity 

解决方案

在这种情况下，您可以使用JavaScript的内置实用程序功能捕获 NaN 和 Infinity :

  let array = [Infinity，-1，6，1，1，0，NaN，0，-1，2，5，10，-无限，NaN，无限，NaN]//以随机顺序将-Infinity，NaN，Infinity排序到末尾array.sort(function(a，b){if(isFinite(a-b)){返回a-b;} 别的 {返回isFinite(a)吗?-1:1;}});//[-1，-1,0,0,1,2,5,6,10，NaN，Infinity，Infinity，NaN，-Infinity，NaN]console.log(array);//sort -Infinity< 0< Infinity< NaNarray.sort(function(a，b){if(isNaN(a)){返回1-isNaN(b);} 别的 {返回a-b;}});//[-Infinity，-1，-1,0,0,1,2,5,6,10，Infinity，Infinity，NaN，NaN，NaN]console.log(array);  

I'm trying to sort an array that sometimes has Infinity or NaN. When I use a standard JavaScript array.sort() it seems to sort until it reaches a NaN and then I get random results after that.

var array =[.02,.2,-.2,Nan,Infinity,20];

Is there a way to still sort this so that the end result is from negative to positive and still have NaN or Infinity at the end.

-.2,.02,.2,20,NaN,Infinity

解决方案

You can catch NaN and Infinity using JavaScript's built-in utility functions for those cases:

let array = [Infinity, -1, 6, 1, 0, NaN, 0, -1, 2, 5, 10, -Infinity, NaN, Infinity, NaN]



//sort -Infinity, NaN, Infinity to the end in random order
array.sort(function(a,b){
  if(isFinite(a-b)) {
    return a-b; 
  } else {
    return isFinite(a) ? -1 : 1;
  }
});

//[-1,-1,0,0,1,2,5,6,10,NaN,Infinity,Infinity,NaN,-Infinity,NaN]
console.log(array);



//sort -Infinity<0<Infinity<NaN
array.sort(function(a,b){
  if(isNaN(a)) { 
    return 1-isNaN(b);
  } else {
    return a-b; 
  }
});

//[-Infinity,-1,-1,0,0,1,2,5,6,10,Infinity,Infinity,NaN,NaN,NaN]
console.log(array);

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