删除数组中的每个第n个元素 [英] Removing every nth element in an array

问题描述

如何删除数组中的每个第n个元素?

How do I remove every nth element in an array?

import numpy as np

x = np.array([0,10,27,35,44,32,56,35,87,22,47,17])
n = 3  # remove every 3rd element

...类似于 x [0 :: n] 的反面吗?我已经尝试过了，但是当然不起作用:

...something like the opposite of x[0::n]? I've tried this, but of course it doesn't work:

for i in np.arange(0,len(x),n):
    x = np.delete(x,i)

推荐答案

您正在关闭...将整个范围作为子切片传递，而不是尝试依次删除每个元素，例如:

You're close... Pass the entire arange as subslice to delete instead of attempting to delete each element in turn, eg:

import numpy as np

x = np.array([0,10,27,35,44,32,56,35,87,22,47,17])
x = np.delete(x, np.arange(0, x.size, 3))
# [10 27 44 32 35 87 47 17]

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