将BitSet转换为Byte [] [英] Converting BitSet to Byte[]

问题描述

我有一个BitSet，需要将其转换为Byte [].但是，通过使用BitSet.toByteArray()，我没有得到正确的输出.我已尝试将Byte []转换为其二进制形式，以检查Bitset和Byte []的二进制形式是否相似.

I have a BitSet, which needs to be converted to a Byte[]. However, by using BitSet.toByteArray(), I don't get the correct output. I have tried converting the Byte[] to its binary form in order to check whether the Bitset and the binary form of the Byte[] are similiar.

public static void generate() {

        BitSet temp1 = new BitSet(64);

        for (int i = 0; i < 64; i++) {
            if(i % 8 != 0 && i < 23) {
            temp1.set(i, true);
            }
        }

        StringBuilder s = new StringBuilder();
        for (int i = 0; i < 64; i++) {
            s.append(temp1.get(i) == true ? 1 : 0);
        }

        System.out.println(s);

        byte[] tempByteKey1 = temp1.toByteArray();

        for (byte b : tempByteKey1) {
            System.out.print(Integer.toBinaryString(b & 255 | 256).substring(1));
        }

    }

输出:

Bitset: 0111111101111111011111100000000000000000000000000000000000000000
Converted Byte: 1111111011111110011111100000000000000000000000000000000000000000

它们都是64位，但是BitSet中的第一个0放置在转换后的其他位置.为什么会发生这种情况，我该如何解决?

They are both 64 bits, but the first 0 in the BitSet is placed somewhere else after the conversion. Why is this happening, and how can I fix it?

推荐答案

来自 BitSet#toByteArray()javadoc :

返回一个新的字节数组，其中包含该位集中的所有位.更准确地说，如果..

Returns a new byte array containing all the bits in this bit set. More precisely, if..

byte[] bytes = s.toByteArray();

然后

bytes.length == (s.length()+7)/8

和

s.get(n) == ((bytes[n/8] & (1<<(n%8))) != 0)

对于所有 n<8 * bytes.length .

@返回一个字节数组，其中包含该位集中所有位的小端序表示法

@return a byte array containing a little-endian representation of all the bits in this bit set

@自1.7起

注意: toByteArray()甚至没有声称知道 size()，对于length()！

Attention: toByteArray() doesn't even claim to know size(), it is only "reliable" regarding length()!

..因此，我建议采用类似以下的方法作为实现(您的 toBinaryString()的替代方法):

..So I would propose as implementation (alternative for your toBinaryString()) a method like:

static String toBinaryString(byte[] barr, int size) {
    StringBuilder sb = new StringBuilder();
    int i = 0;
    for (; i < 8 * barr.length; i++) {
        sb.append(((barr[i / 8] & (1 << (i % 8))) != 0) ? '1' : '0');
    }
    for (; i < size; i++) {
        sb.append('0');
    }
    return sb.toString();
}

..这样称呼:

System.out.println(toBinaryString(bitSet.toByteArray(), 64);

---

run:
0111111101111111011111100000000000000000000000000000000000000000
0111111101111111011111100000000000000000000000000000000000000000
BUILD SUCCESSFUL (total time: 0 seconds)

这篇关于将BitSet转换为Byte []的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！