在Swift中创建数组时为什么会出现错误? [英] Why do I get an error when creating an array in Swift?

问题描述

在我的程序中，我有一个带有一些值的数组:

In my program I have an array with some values:

let pointArray = [
    [[185,350],8],
    [[248.142766340927,337.440122864078],5],
    [[301.67261889578,301.67261889578],5],
    [[337.440122864078,248.142766340927],5],
    [[350,185],8],
    [[327.371274561396,101.60083825503],5],
    [[301.67261889578,68.3273811042197],5],
    [[248.142766340927,32.5598771359224],5],
    [[185,20],8],
    [[101.60083825503,42.6287254386042],5],
    [[68.3273811042197,68.3273811042197],5],
    [[42.6287254386042,101.60083825503],5],
    [[20,185],8],
    [[32.5598771359224,248.142766340927],5],
    [[68.3273811042197,301.67261889578],8],
    [[101.60083825503,327.371274561396],5]
]

编译时出现以下错误:

表达过于复杂，无法在合理的时间内解决；考虑将表达式分成不同的子表达式

Expression was too complex to be solved in reasonable time; consider breaking up the expression into distinct sub-expressions

为什么会出现错误?仅仅是因为数组太大了吗?

Why am I getting the error? Is it just because the array is too large?

推荐答案

Swift编译器通常不满意，如果您给它一个大数组而不告诉它类型.它必须解析所有这些数据以尝试推断类型.如果声明数组的类型，它将起作用:

The Swift compiler is generally not happy if you give it a big array without telling it the type. It has to parse all of that data to try to infer a type. It will work if you declare the type of the array:

let pointArray:[[Any]] = [[[185,350],8],[[248.142766340927, ...

但是，您必须强制转换以读取值.您应该真正考虑将值放入结构中，并让数组保留该值.

But, you'll have to cast to read the values. You should really consider putting your values into a struct and letting the array hold that.

对于您的数据，元组数组也可以很好地工作:

For your data, an array of tuples might also work nicely:

let pointArray:[(point: [Double], count: Int)] = [
    ([185,350],8),
    ([248.142766340927,337.440122864078],5),
    ([301.67261889578,301.67261889578],5)

]

let point = pointArray[0].point  // [185, 350]
let count = pointArray[0].count  // 8

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