javascript旋转数组元素 [英] javascript rotate array elements

问题描述

大家好，我有这个任务:我有一个数组[4,7,3,6,9]，我必须制作一个像这样的数组:

Hello, everybody, I have this task: I have an array [4,7,3,6,9] and I have to make an array like this:

[4,7,3,6,9]
[9,4,7,3,6]
[6,9,4,7,3]
[3,6,9,4,7]
[7,3,6,9,4]

即使我向数组添加新项目，我也必须编写一个数组旋转的程序.我是JS的新手，大约1周左右，这是我目前的尝试:

I have to make a program where array is rotating even if I add a new item to an array it should change accordingly. I am total newbie at JS, 1 week or so, here is my current try:

var numbers = [4, 7, 3, 6, 9];
console.log(numbers);
numbers[0] = 9; numbers[1] = 4; numbers[2] = 7; numbers[3] = 3; numbers[4] = 6;
console.log(numbers);
numbers[0] = 6; numbers[1] = 9; numbers[2] = 4; numbers[3] = 7; numbers[4] = 3;
console.log(numbers);
numbers[0] = 3; numbers[1] = 6; numbers[2] = 9; numbers[3] = 4; numbers[4] = 7;
console.log(numbers);
numbers[0] = 7; numbers[1] = 3; numbers[2] = 6; numbers[3] = 9; numbers[4] = 4;
console.log(numbers);

在我看来，我也有.push，.splice等.我不知道为什么，但是我真的觉得javascript不适合我的大脑，哈哈:D

Also in my mind I have .push, .splice, etc. I dont know why but i really feel that javascript is not for my brain, haha :D

推荐答案

您可以弹出该值并将其取消移位.

You could pop the value and unshift it.

var array = [4, 7, 3, 6, 9],
    i = array.length;

while (i--) {
    console.log(array.join(' '));
    array.unshift(array.pop());
}
console.log(array.join(' '));

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