给定一个数组数组，如何将所有空值替换为0? [英] Given an array of arrays, how can I replace all empty values with 0?

问题描述

示例数组

$myArray[0] = array('23', null, '43', '12');
$myArray[1] = array(null, null, '53', '19');
$myArray[2] = array('12', '13', '14', null);

所有null都应替换为0.我希望有人能够以一种有效的方式做到这一点，也许是我不知道的内置PHP函数.

All nulls should be replaced with 0. I was hoping someone would have an efficient way of doing this, perhaps a built in PHP function that I am unaware of.

推荐答案

您可以使用 array_walk_recursive 函数，其回调函数将 null 替换为 0 .

You could use the array_walk_recursive function, with a callback function that would replace null by 0.

例如，考虑以这种方式声明数组:

For example, considering your array is declared this way :

$myArray[0] = array(23, null, 43, 12);
$myArray[1] = array(null, null, 53, 19);
$myArray[2] = array(12, 13, 14, null);

注意:我以为您输入了错字，并且您的数组不仅包含一个字符串，还包含多个子元素.

您可以使用这种代码:

You could use this kind of code :

array_walk_recursive($myArray, 'replacer');
var_dump($myArray);

使用以下回调functon:

With the following callback functon :

function replacer(& $item, $key) {
    if ($item === null) {
        $item = 0;
    }
}

请注意:

• 第一个参数通过引用传递！
  • 这意味着对其进行修改将修改您数组中的相应值

  
  然后您将得到以下输出:

  
  And you'd get the following output :

  array
    0 => 
      array
        0 => int 23
        1 => int 0
        2 => int 43
        3 => int 12
    1 => 
      array
        0 => int 0
        1 => int 0
        2 => int 53
        3 => int 19
    2 => 
      array
        0 => int 12
        1 => int 13
        2 => int 14
        3 => int 0
  

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