简单的HTML DOM-如何获取dt/dd元素进行数组排列? [英] Simple html dom - how get dt/dd elements to array?

问题描述

可能重复:
仅从使用过的html表中获取数据preg_match_all在php

HTML:

   <div class="table">
       <dl>
            <dt>ID:</dt>
            <dd>632991</dd>
            <dt>Type:</dt>
            <dd>NEW</dd>
            <dt>Body Type:</dt>
            <dd>Compact</dd>
        </dl>
    </div>

在PHP中使用simple_html_dom来获得此效果的最佳方法是什么:

What's is the best way to get this using simple_html_dom in PHP:

PHP:

$option = array(
    'id' => 632991,
    'Type' => 'NEW',
    'Body Type' => 'Compact'
 );

推荐答案

您可以使用XPath:

You could use XPath:

按类名获取DOM元素

获取元素ByTag名称

使用PHP获取DOM元素

在Stackoverflow上有很多帖子.在此处使用搜索.

Here are a lot of posts on Stackoverflow. Use the search here.

<?php

$dom = new DOMDocument();
$dom->loadHTML('<div class="table">
       <dl class="list">
            <dt>ID:</dt>
            <dd>632991</dd>
            <dt>Type:</dt>
            <dd>NEW</dd>
            <dt>Body Type:</dt>
            <dd>Compact</dd>
        </dl>
    </div>');

$nodes = $dom->getElementsByTagName('dl');
foreach ($nodes as $node) {
    var_dump(getArray($node));
}

function getArray($node) { 
    $array = false; 

    if ($node->hasAttributes()) { 
        foreach ($node->attributes as $attr) { 
            $array[$attr->nodeName] = $attr->nodeValue; 
        } 
    } 

    if ($node->hasChildNodes()) { 
        if ($node->childNodes->length == 1) { 
            $array[$node->firstChild->nodeName] = $node->firstChild->nodeValue; 
        } else { 
            foreach ($node->childNodes as $childNode) { 
                if ($childNode->nodeType != XML_TEXT_NODE) { 
                    $array[$childNode->nodeName][] = getArray($childNode); 
                } 
            } 
        } 
    } 
    return $array; 
} 
?>

getArray函数来自php.net

The function getArray is from php.net

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