正则表达式用于[]之间的任何内容 [英] Regex for anything between []

问题描述

我需要找到[]的正则表达式

I need to find the regex for []

例如，如果字符串为-[Stack]这是我需要[查找]的[Tag].

For eg, if the string is - Hi [Stack], Here is my [Tag] which i need to [Find].

它应该返回堆叠，标记，查找

It should return Stack, Tag, Find

推荐答案

非常简单，您只需要(1)用反斜杠转义括号，(2)使用(.*?)捕获内容.

Pretty simple, you just need to (1) escape the brackets with backslashes, and (2) use (.*?) to capture the contents.

\[(.*?)\]

括号是一个捕获组，它们捕获其内容供以后使用..* 之后的问号使匹配的内容变得非贪婪.这意味着它将匹配可能的最短匹配，而不是最长匹配.当一行中有多个匹配项时，贪婪和非贪婪的区别就会出现:

The parentheses are a capturing group, they capture their contents for later use. The question mark after .* makes the matching non-greedy. This means it will match the shortest match possible, rather than the longest one. The difference between greedy and non-greedy comes up when you have multiple matches in a line:

Hi [Stack], Here is my [Tag] which i need to [Find].
   ^______________________________________________^

贪婪的匹配将在两组方括号之间找到最长的字符串.那是不对的.非贪婪的匹配会找到最短的匹配:

A greedy match will find the longest string possible between two sets of square brackets. That's not right. A non-greedy match will find the shortest:

Hi [Stack], Here is my [Tag] which i need to [Find].
   ^_____^

无论如何，代码最终将看起来像:

Anyways, the code will end up looking like:

string regex = @"\[(.*?)\]";
string text  = "Hi [Stack], Here is my [Tag] which i need to [Find].";

foreach (Match match in Regex.Matches(text, regex))
{
    Console.WriteLine("Found {0}", match.Groups[1].Value);
}

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