获取文件名的字节数组或流 [英] Get file name from byte array or Stream

问题描述

是字节数组或流可能获取文件名？ 我不想保存文件。我只是想找回这个名字。

Is possible get filename from byte array or stream? I do not want to save the file. I just want to retrieve the name.

推荐答案

如果在流实际上是一个的FileStream ，那么这个的可以的可强制转换为的FileStream 和访问 .Name点属性：

If the Stream is actually a FileStream, then this may be available by casting to FileStream and accessing the .Name property:

Stream stream = ...
FileStream fs = stream as FileStream;
if(fs != null) Console.WriteLine(fs.Name);

不过，在一般情况下：不，这是不可用的。 A 字节[] 的确实的文件的文件名的概念，也没有大多数其他类型的数据流。同样，的FileStream 基本流被包裹其他流（COM pression，加密，缓冲等）将不会公开这样的信息，尽管底层的流（几层向下）是一个文件。

However, in the general case: no, this is not available. A byte[] certainly has no concept of a filename, nor do most other types of streams. Likewise, a FileStream base-stream that is being wrapped by other streams (compression, encryption, buffering, etc) will not expose such information, despite the underlying stream (several layers down) being a file.

我会分开处理的文件名。

I would handle the filename separately.

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