.NET 4.5异步等待和重载方法 [英] .NET 4.5 async await and overloaded methods

问题描述

我有一个异步方法：

public async Task<UserLoginExResult> LoginExAsync(CustomTable exRequest, string language, bool throwEx = true)
{
    UserLoginExResult result = await UserService.LoginExAsync(UserGroup, language, TimezoneOffset, GetDeviceInfo(), GetLoginProperties(), exRequest);

    ProcessLoginResult(result, false, throwEx);

    return result;
}

和过载：

public Task<UserLoginExResult> LoginExAsync(CustomTable exRequest, bool throwEx = true)
{
    return LoginExAsync(exRequest, Language.ID, throwEx);
}

我不知道我是否应该标注超载一（一个具有较少参数）为异步和使用计谋？我想我不应该，但你能告诉我什么发生对子级，如果我这样做吗？我很迷失在这里，而不是真的知道什么工作它会等待？它会创建一个额外的工作或等待不创建一个新的工作？

I'm not sure if I should mark the overloaded one (the one with fewer parameters) as async and use await? I guess I should not but can you tell me what whould happen if I would do that? I'm quite lost in here and not really sure what Task it would wait for? Would it create an extra Task or await doesn't create a new Task?

推荐答案

没有，有一个在使用异步方法时，它是没有什么好处的只是的去包装和解开一个已经存在的。它的优良只是有一个正常的方法，在这里，委托给真正的异步方法。

No, there's little benefit in using an async method when it's just going to wrap and unwrap an existing one. It's fine to just have a "normal" method here, delegating to the "real" async method.

（他们不是的非常的相同 - 例如，如果 UserService.LoginExAsync 方法抛出一个异常，而不是返回一个失败的任务，异步/计谋版本将只返回一个失败的任务，而其他版本的也的立即抛出。）

(They're not quite the same - for example, if the UserService.LoginExAsync method throws an exception rather than returning a failed task, the async/await version will just return a failed task, whereas the other version will also throw immediately.)

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