Exchange.getIn（）。getBody（）返回在第二个电话骆驼空字符串 [英] Exchange.getIn().getBody() returns empty string in camel on second call

问题描述

我有2个相同的呼叫：

String msg1 = exchange.getIn().getBody(String.class);
String msg2 = exchange.getIn().getBody(String.class);

在MSG1我得到正确的预期值，但MSG 2是一个空字符串。我不是设置在走出消息，左右交换在信息应该是仍然完好无损。请解释为什么会这样。

In msg1 I get the correct expected value , but msg2 is an empty string. I'm not setting the Out message , so the exchange In message should be still intact. Please explain why this is happening.

骆驼路线：

<camelContext xmlns="http://camel.apache.org/schema/spring">
    <route id="route1">
        <from uri="timer://myTimer?period=2000" />
        <setBody>
            <simple>Hello World ${header.firedTime}</simple>
        </setBody>
        <process ref="messageProcessor" />
        <to uri="http://localhost:8090"/>
    </route>
    <route id="route2">
        <from uri="jetty://http://localhost:8090" />
        <process ref="messageProcessor" />
    </route>
</camelContext>

处理器包含只由上述2语句。
在ROUTE1的处理是正确的，但在路径2我得到的描述的行为：第一个电话 - 有效的字符串，第二个电话 - 空字符串。所以我想，也许它是与HttpMessage转换。

The processor contains only the 2 statements from above. The processing in route1 is correct , but in route2 I get the described behaviour : first call - valid string , second call - empty string. So I think maybe it has something to do with HttpMessage conversion.

推荐答案

http://camel.apache.org/jetty。 HTML

Jetty是基于流的，这意味着它接收​​输入提交
  骆驼作为流。这意味着你将只能阅读
  流一次的内容。

Jetty is stream based, which means the input it receives is submitted to Camel as a stream. That means you will only be able to read the content of the stream once.

只需将输入字符串中的前使用两次或更多次

Just convert the input in a String before use it twice or more times

<route id="route2">
    <from uri="jetty://http://localhost:8090" />
    <convertBodyTo type="String" />
    <process ref="messageProcessor" />
</route>

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