数据注释正则表达式 [英] Data annotation regular expression

问题描述

我需要一个正则表达式来表示这样的字符串:

I need a regular expression for a string like this:

例如1234-1234-12345

ex. 1234-1234-12345

前两个数字必须在01-18之间，并且整个字符串必须为15个字符长

where the first two numbers must be between 01-18 and the whole string must be 15 characters long

示例:0511-xxxx-xxxxx.

example: 0511-xxxx-xxxxx.

我尝试使用 [RegularExpression(@"^ [0-9] {1,18} $"，ErrorMessage =无效的ID.")]

但是它不起作用，它甚至给我一个错误，说'，'丢失了.

but it doesnt work, it even gives me an error that says ',' is missing.

让它变得更容易，它是一个13位字符的数字字符串，其中前两位必须在01-18之间.

Lets make it even easier, a numeric string 13 character long where the first two digits must be between 01-18.

例如1234567890123

Ex. 1234567890123

(我更喜欢第一种格式，但这种格式也可以).

(I would prefer the first format but this one work too).

我不知道如何使用Regex，所以如果有人可以给我一个指向我可以学习的地方的链接，我将非常感激.

I don't know how to use Regex so if someone can kindly give me a link to somewhere I can learn I would very much appreciate it.

而且，最重要的是，如果有更好的方法可以解决此问题而无需使用Regex，我也将不胜感激.

And, most importantly, if there is a better way to get around this without using Regex I would appreciate it as well.

显然，我的要求不清楚.我想要的是前两位数字(XXxx-xxxx-xxxxx)为01、02、03、04、05、06、07、08、09、10、11、12、13、14、15、16、17，18.

Apparently, my request is a little unclear. What I want it that the first two digits (XXxx-xxxx-xxxxx) be 01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 11, 12, 13, 14, 15, 16, 17, 18.

推荐答案

您的前两个数字"有点不清楚，但是如何:

Your "first two numbers" is a little unclear, but how about:

var pattern = @"(0\d|1[0-8])\d\d-\d{4}-\d{5}";

如果您要匹配整个字符串而不仅仅是找到子字符串，则需要

If you want to match the whole string and not just find the substring, you need

var pattern = @"^(0\d|1[0-8])\d\d-\d{4}-\d{5}$";

如果您没有用连字符将组分开，请使用:

If you didn't have the groups separated by hyphens, use:

var pattern = @"^(0\d|1[0-8])\d{11}$";

您可以像使用它

Regex.IsMatch(aString, pattern)

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