如何将Stream转换为对象 [英] How to convert a Stream into an object

问题描述

如何将流转换为对象.

我有一个WebApi

I have a WebApi

[HttpGet]
    public AttachmentViewModel DownloadAttachementDetailsByIds(int attachementDetaisId)
    {
        AttachmentViewModel attachment = new AttachmentViewModel
        {
            AttachmentName = "Observe",
            AttachmentType = ".c",
            AttachmentDetailsID = 123,
            AttachmentDetails = Encoding.ASCII.GetBytes("some contant"),
            AttachmentSize = 12 //some valid size
        };

        return attachment;
    }

现在我将这个GET方法称为波纹管:

Now I'm calling this GET method as bellow:

 WebClient webClient = new WebClient();
 Stream stream = webClient.OpenRead(documentRepositoryApiUrl + "DocRepoApi/DownloadAttachementDetailsById?attachementDetaisId=97");

好吧，我的呼叫成功了，但是一旦我将所有数据输入流中，如何再次将它们作为相同的 AttachmentViewModel 对象进行检索.并且如果API返回任何错误，如何读取它.

Well, my call is successful but once I get all data into my stream how can I again retrieve them all as the same AttachmentViewModel object. And if the API returns any error how to read it.

推荐答案

您可以使用

You can use the DownloadString method from WebClient and deserialize it into your model (by using JSON.NET for example).

WebClient webClient = new WebClient();
var data = webClient.DownloadString(url);
var deserialized = JsonConvert.DeserializeObject<AttachmentViewModel>(data);

如果发生错误，将抛出相应的 WebException .

If an error occurs, a corresponding WebException will be thrown.

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