最佳实践-警告:方法缺少“等待"操作员警告 [英] Best practice - warning: method lacks 'await' operator warning

问题描述

是的，我知道还有其他问题可以解决此警告的含义以及如何解决它，但是，我有一个关于异步编程的最佳实践的问题.

Yes, I know there are other questions to cover what this warning means and how to solve it, however, I have a question about best practices regarding async programming.

我有一个服务层，负责处理数据层和表示层之间的数据传输.该服务包含几种查询数据库并返回结果的方法.

I have a service layer which handles data transfer between the data layer and the presentation layer. This service contains several methods which query the database, and return the result.

我一直在尝试使用异步编程.一个例子:

I have been trying to use async programming wherever possible. An example:

    public async Task<SiteTemplateResource[]> GetResources(int siteTemplateId, string extension)
    {
        return await Database.FindBy<SiteTemplateResource>(str => str.SiteTemplateId == siteTemplateId && str.HashedFile.EndsWith(extension)).ToArrayAsync();
    }

我的问题是，除了 ToArrayAsync 调用之外，我实际上没有等待任何事情，而我真的不需要.

My problem with this is, I'm not actually awaiting anything, other than to the ToArrayAsync call, which I don't really need.

我应该继续使用异步/等待吗?例如，我将如何等待此功能的任何结果:

Should I go ahead and use async/await for this? And how would I for example await anything for this function:

    public async Task<int> SiteTemplateBySiteIdAsync(int siteId)
    {
        return Database.First<SiteSiteTemplate>(sst => sst.SiteId == siteId).SiteTemplateId;
    }

在该函数中我什么都不需要等待，但是我也不需要调用 ToArrayAsync ，因此在上述情况下如何避免出现方法缺少'await'运算符"警告?

I don't await anything in that function, but I also don't need to call ToArrayAsync, so how do I avoid the warning "method lacks 'await' operator" in above case?

谢谢.

推荐答案

如果您不需要通过某种方法进行 await ，则该方法需要 async (无论出于何种原因)，您可以使用 Task.FromResult ，可以等待:

If you have nothing to await in a method that needs to be async (for whatever reason), you can use Task.FromResult, which can be awaited:

public async Task<int> SiteTemplateBySiteIdAsync(int siteId)
{
    return await Task.FromResult(Database.First<SiteSiteTemplate>(sst => sst.SiteId == siteId).SiteTemplateId);
}

如果不需要 async 方法，则可以简单地添加 async Task< int> 并将其替换为 int .

If you don't need the async method, you can simply more the async Task<int> and replace it for int.

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