加入所有异步调用以返回一些结果 [英] join all async calls to return some result

问题描述

对于这个问题，我想进行一些异步调用，最后等到所有调用完成，然后返回结果，该解决方案将是什么?

What will be the performant solution for this problem where I want to make some async calls, wait in last until all the calls are completed, then return the result.

function parseAndMatch(arg1, arg2){
   async.all([
      asyncCall1(arg1, arg2),
      asyncCall2(arg1, arg2)]
   ).then( result => {
      //do something with result;
      return finalResult;
   });
}

我尝试安装npm deasync ， asyncawait ， bluebird 和 async 软件包来解决此问题.但是我找不到解决方案.

I tried to fit npm deasync, asyncawait, bluebird, and async packages to solve this problem. But I couldn't find the solution.

推荐答案

在@wing答案的基础上，我使用本机 Promise 和npm deasync 库解决了此问题.但是我不确定它的效率和性能如何.

On the basis of @wing answer's I solved this problem using native Promise and npm deasync library. But I'm not sure how efficient and performant it is.

function parseAndMatch(callback) {
  return Promise.all([
      new Promise(function(resolve, reject) {
            var sum = 1;
            for (var i = 0; i < 10000; i++) {
                sum++;
            }
            return resolve(sum);
      }),
      new Promise(function(resolve, reject) {
            var sum = 1;
            for (var i = 0; i < 90000; i++) {
                sum++;
            }
            return resolve(sum);
      }),
  ]);
}

function joinAndReturn(){
    var done = false;
    var result;
    parseAndMatch().then((results) => {
        result = results[0] + results[1];
        done = true;
    });
    deasync.loopWhile(function(){return !done;});
    return result;
}

console.log(joinAndReturn());//100002

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