Python smtplib send_message()失败，返回AttributeError:'str'对象没有属性'get_all' [英] Python smtplib send_message() failing, returning AttributeError: 'str' object has no attribute 'get_all'

问题描述

我正在一个项目中，我必须使用Python 3.4中的smtplib和email模块发送电子邮件.

I'm working on an project where I have to use the smtplib and email modules in Python 3.4 to send an email.

我可以自己创建电子邮件，也可以连接到服务器，但是它会返回此异常:

I'm able to create the email itself and I'm able to connect to the server, but then it returns this Exception:

reply: b'235 2.7.0 Accepted\r\n'
reply: retcode (235); Msg: b'2.7.0 Accepted'
send: 'QUIT\r\n'
reply: b'221 2.0.0 closing connection s66sm8304113yhp.2 - gsmtp\r\n'
reply: retcode (221); Msg: b'2.0.0 closing connection s66sm8304113yhp.2 - gsmtp'
Traceback (most recent call last):
  File "base.py", line 108, in <module>
    send(fromaddr, toaddrs, msg)
  File "base.py", line 61, in send
    server.send_message(fromaddr, toaddrs, msg)
  File "/usr/lib/python3.4/smtplib.py", line 829, in send_message
    resent = msg.get_all('Resent-Date')
AttributeError: 'str' object has no attribute 'get_all'

该代码(麻烦的行直接链接到)可用此处.奇怪的是，代码实际上在实际发送任何电子邮件正文之前先发送了QUIT-不知道这是否会影响到电子邮件.

The code (troublesome line linked directly to) is available here. Strangely enough, the code actually sends QUIT prior to actually sending any of the email body - not sure if that's something that would affect this.

有人知道导致此错误的原因吗?

Does anyone know what is causing this error?

EDIT (事实证明)，这部分原因是我使用了错误的格式.send_message()要求变量以消息，发件人，收件人的顺序发送，而我的代码以发件人，收件人，消息的顺序发送变量.

EDIT Turns out that part of my issue was that I was using the incorrect format. send_message() requires the variables in the order of Message, From, To, while my code was sending it in the order of From, To, Message.

但是，我现在收到此错误:

However, I'm now getting this error:

reply: b'235 2.7.0 Accepted\r\n'
reply: retcode (235); Msg: b'2.7.0 Accepted'
send: 'QUIT\r\n'
reply: b'221 2.0.0 closing connection s66sm8443316yhp.2 - gsmtp\r\n'
reply: retcode (221); Msg: b'2.0.0 closing connection s66sm8443316yhp.2 - gsmtp'
Traceback (most recent call last):
  File "MIME-base.py", line 108, in <module>
    send(fromaddr, toaddrs, msg)
  File "MIME-base.py", line 61, in send
    server.send_message(msg, fromaddr, toaddrs)
  File "/usr/lib/python3.4/smtplib.py", line 839, in send_message
    g.flatten(msg_copy, linesep='\r\n')
  File "/usr/lib/python3.4/email/generator.py", line 109, in flatten
    self._write(msg)
  File "/usr/lib/python3.4/email/generator.py", line 189, in _write
    self._write_headers(msg)
  File "/usr/lib/python3.4/email/generator.py", line 416, in _write_headers
    self._fp.write(self.policy.fold_binary(h, v))
  File "/usr/lib/python3.4/email/_policybase.py", line 325, in fold_binary
    folded = self._fold(name, value, sanitize=self.cte_type=='7bit')
  File "/usr/lib/python3.4/email/_policybase.py", line 352, in _fold
    parts.append(h.encode(linesep=self.linesep,
AttributeError: 'list' object has no attribute 'encode'

推荐答案

SMTP.sendmail .因此，尝试:

The signature for SMTP.send_message is not the same as SMTP.sendmail. So try:

    server.send_message(msg, fromaddr, toaddrs)

编辑:

您还需要单独添加 To:标头，而不是将其添加为列表:

You also need to add the To: headers separately, rather than as a list:

    for item in input("To: ").split():
        msg['To'] = item

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