Python静音音频文件的特定部分 [英] Python silence specific part of audio file

问题描述

我有一个音频文件 audio.wav ，并且有一系列时间框架，如下所示:

I have an audio file audio.wav and I have an array of time frames looking like this one:

X = [(12.31，14.)，(15.4，18.9)，...]

这些是我希望在拥有的.wav音频文件中完全保持静音的时间范围.我该如何实现?

These are the time frames that I would like to be completely silent in a .wav audio file that I have. How can I achieve this?

推荐答案

根据您的链接，我将其视为

Based on your link I see it as

from pydub import AudioSegment

a = AudioSegment.from_wav("audio.wav")

# X = [(12.31, 14.), (15.4, 18.9), ...]

duration = (14.0 - 12.31) * 1000
s1 = AudioSegment.silent(duration)

duration = (18.9 - 15.4) * 1000
s2 = AudioSegment.silent(duration)

b = a[:12310] + s1 + a[14000:15400] + s2 + a[18900:]

b.export('new_audio.wav', format='wav')

现在的问题是使用 for 循环使其自动化

now problem is to use for-loop to automate it

我无法对其进行测试，但我将其视为

I can't test it but I see it as

from pydub import AudioSegment

a = AudioSegment.from_wav("audio.wav")

X = [(12.31, 14.), (15.4, 18.9)]

parts = []

# start for audio
begin = 0

for start, end in X:
    # keep sound before silence
    s = a[begin*1000:start*1000]
    parts.append(s)  
    
    # create silence
    duration = (end - start) * 1000
    s = AudioSegment.silent(duration)
    parts.append(s)

    # value for next loop
    begin = end

# keep part after last silence
parts.append(a[begin*1000:])

# join all parts using standard `sum()` but it need `parts[0]` as start value   
b = sum(parts[1:], parts[0])

# save it
b.export('new_audio.wav', format='wav')

这篇关于Python静音音频文件的特定部分的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！