无服务器框架Python lambda直接返回JSON [英] Serverless Framework Python lambda return JSON directly

问题描述

我试图找出如何使用无服务器框架直接将响应作为JSON返回.这是具有Lambda代理集成的AWS上的功能.所有默认设置.目标是从python lambda函数中，HTTP响应客户端直接获取的是JSON对象，而不是JSON的字符串序列化.

I'm trying to find out how can I return the response as a JSON directly using Serverless Framework. This is a function on AWS with Lambda Proxy Integration. All default setting. The goal is to from the python lambda function, the HTTP response client gets is directly a JSON object, instead of a string serialization of a JSON.

python处理程序与这个处理程序一样简单

The python handler is as simple as this one

    def handle(event, context):
        log.info("Hello Wold")
        log.info(json.dumps(event, indent=2))
        return {
            "statusCode": 200,
            "body": {"foo": "bar"},
            "headers": {
                "Content-Type": "application/json"
            }
        }

函数如下:

    functions:
      report:
        handler: handler.handle
        events:
          - http:
              path: api/mypath
              method: post
              authorizer: aws_iam

使用这些配置，我在Postman中得到的响应BODY是:

With these configurations, the response BODY I get in Postman is:

    {
        "statusCode": 200,
        "body": {
            "foo": "bar"
        },
        "headers": {
            "Content-Type": "application/json"
        }
    }

所以这很奇怪，为什么我把一切都当成身体?如何正确配置它以便只获得真实"主体?

So this is strange, why I get everything as body? How do I configure it properly so that I only get the "real" body?

推荐答案

方法#1

使用json.dumps()将JSON转换为字符串.

approach #1

Use json.dumps() to convert JSON to string.

import json
def handle(event, context):
    log.info("Hello Wold")
    log.info(json.dumps(event, indent=2))
    return {
        "statusCode": 200,
        "body": json.dumps({"foo": "bar"}),
        "headers": {
            "Content-Type": "application/json"
        }
    }

方法2

使用lambda集成，避免使用json.dumps().但这会将您的输出转换为

approach #2

Use lambda integration and avoid json.dumps(). But this will transform your output as

{ foo = bar}

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