更新的文档的MSWord使用Apache POI [英] Updating an MSWord document with Apache POI

问题描述

我试图更新使用Apache POI一个Microsoft Word文档。该MSWORD文件是包含了许多形式$ {} place.holder和所有我需要做的是具体的值替换持有者占位符的模板。我已经得到了迄今

I'm trying to update a Microsoft Word document using Apache POI. The msword document is a template that contains a number of placeholders in the form "${place.holder}" and all I need to do is to replace the holders with specific values. What I've got so far is

private void start() throws FileNotFoundException, IOException {

    POIFSFileSystem fsfilesystem = null;
    HWPFDocument hwpfdoc = null;

    InputStream resourceAsStream =  getClass().getResourceAsStream("/path/to/document/templates/RMA FORM.doc");       
    try {
        fsfilesystem = new POIFSFileSystem(resourceAsStream );
        hwpfdoc = new HWPFDocument(fsfilesystem);
        Range range = hwpfdoc.getRange();

        range.replaceText("${rma.number}","08739");
        range.replaceText("${customer.name}", "Roger Swann");

        FileOutputStream fos = new FileOutputStream(new File("C:\\temp\\updatedTemplate.doc"));
        hwpfdoc.write(fos);
        fos.flush();
        fos.close();

    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

}

程序运行没有错误。如果我看在输出文件用十六进制编辑器，我可以看到占位符已被替换的程序。然而，当我尝试打开与的MSWord文档，崩溃的MSWord。

The program runs without errors. If I look in the output file with a Hex editor I can see that the placeholders have been replaced by the program. However, when I try to open the document with MSWord, MSWord crashes.

有没有办法，我的思念，还是我基本上是运气与此步骤（一系列步骤）？我是否需要调整任何计数器，因为替换文本的长度是不一样的替换文本的长度？

Is there a step (series of steps) that I'm missing, or am I basically out of luck with this? Do I need to adjust any counters because the length of the replacement text is not the same as the length of the replaced text?

问候

推荐答案

使用新的FileInputStream（）而不是的getClass（）。的getResourceAsStream（ /路径/到/文件/模板/ RMA表.doc）;

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