检查窗口是否在后台Tkinter中 [英] Check if window is in background Tkinter

问题描述

因此，我正在尝试在 tkinter 上制作一个应用.我刚刚开始学习此模块的工作原理.

So, I'm trying to make an app on tkinter. I've just started learning how this module works.

在我的应用程序中，我有一个根窗口和一个子窗口(最高级别)，并将该子窗口设置为始终位于顶部.当我最小化根窗口时，子窗口也将最小化，因为我已经定义了该条件.我的问题是当我选择其他窗口时.当我这样做时，子窗口仍然停留在顶部，我想知道是否有一种方法可以知道我的根窗口是否在后台，也就是:我目前不在使用它(例如 root).winfo _... 函数).

In my app, I have a root window and a child (top leveled) window, and I set the child to be always on top. When I minimize my root window, the child window also minimizes, because I have defined that condition. My problem is when I select other window. When I do it, the child window still stays on top and I want to know if there is a way to know if my root window is in background, a.k.a.: I'm not currently working on it (like a root.winfo_... function).

我可以提供其他示例，因为我觉得我并没有以您理解的方式来解释我的问题.我也可以提供我的代码，但是我认为现在是必须的.

I can provide other examples as I feel that I am not explaining my problem in a way that you understand. I can also provide my code but I think that is now necessary.

推荐答案

问题:检查窗口是否在后台

使用 tk.self.winfo_ contains(... ，您可以确定是否在顶层中显示窗口小部件(此处是 root 窗口)>.在此示例中，给定窗口的中心用作可见点.

Using tk.self.winfo_containing(... you can determine if a widget, here the root window, is shown at Top Level. In this example, the center of the given window is used as visible point.

注意:在移动窗口时，结果可能为 False .

Note: While you move the window, the result may be False.

参考:- Tkinter.Widget.winfo_ contains-method

将小部件返回给定位置，或者返回无

Returns the widget at the given position, or None

---

import tkinter as tk


class App(tk.Tk):
    def __init__(self):
        super().__init__()

        self.is_toplevel()

    def is_toplevel(self):
        width, height, x, y = self.winfo_width(), self.winfo_height(), \
                              self.winfo_rootx(), self.winfo_rooty()

        if (width, height, x, y) != (1, 1, 0, 0):
            is_toplevel = self.winfo_containing(x + (width // 2),
                                                y + (height // 2)
                                                ) is not None

            print('is_toplevel: {}'.format(is_toplevel))

        self.after(2000, self.is_toplevel)


if __name__ == "__main__":
    App().mainloop()

使用Python测试:3.5-'TclVersion':8.6'TkVersion':8.6-Linux
注意:已确认，可在 Windows 上运行.
可能不适用于 MACOS .

Tested with Python: 3.5 - 'TclVersion': 8.6 'TkVersion': 8.6 - Linux
Note: Confirmed, works on Windows.
May not work on MACOS.

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