XCTest UI测试-如何在不重新启动的情况下关闭和打开应用程序? [英] XCTest UI Testing - How to close and open an app without relaunch?

问题描述

我想让我的应用程序进入后台，然后又回到前台.

I want to make my app to go to background, and then comeback to the foreground.

要使应用程序进入后台，请执行以下操作: XCUIDevice.shared().press(XCUIDeviceButton.home)

To make an app to go background: XCUIDevice.shared().press(XCUIDeviceButton.home)

要终止应用(强制点击): XCUIApplication().terminate()

To terminate an app(force tap): XCUIApplication().terminate()

要启动该应用程序: XCUIApplication().launch()

问题:当我尝试关闭并打开该应用程序时，launch()方法从后台清除该应用程序，并重新打开该应用程序.

Problem: when I try to close and open the app, the launch() method clears the app from background and it opens the app freshly.

我看到了此评论.但是无法在UI测试中弄清楚.我正在使用Swift.需要帮助！

I saw this comment regarding this. But cant able to figure out it in UI test. I'm using Swift. Help needed!!

推荐答案

从Xcode 9和iOS 11开始， XCUIApplication()具有您可以使用的 activate()方法可以用来重新启动该应用.

As of Xcode 9 and iOS 11, XCUIApplication() has an activate() method that you can use to relaunch the app.

按照brandenbyers的建议，您可以按下"主屏幕按钮以使应用程序后台运行，然后像这样再次激活它以避免使用Siri:

As brandenbyers suggested, you can "press" the home button to background your app, and then activate it again like this to avoid using Siri:

XCUIDevice.shared.press(.home)
XCUIApplication().activate()

请注意，这仅适用于使用XCUITest构建的目标，而不适用于XCTest.如果在XCTest构建的目标中尝试此操作，则所有XCUIApplication操作都将崩溃.

Note that this only works with targets built using XCUITest, not XCTest. If you try this within a target built from XCTest, all XCUIApplication operations will crash.

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