如何在不产生两个进程的情况下以其他用户身份运行nohup? [英] How do I run nohup as a different user without spawning two processes?

问题描述

我正在尝试nohup命令并以其他用户身份运行它，但是每次执行此操作时，都会产生两个进程.

I'm trying to nohup a command and run it as a different user, but every time I do this two processes are spawned.

例如:

$ nohup su -s /bin/bash nobody -c "my_command" > outfile.txt &

这肯定以没有人的身份运行my_command，但是我不想显示一个额外的过程:

This definitely runs my_command as nobody, but there's an extra process that I don't want to shown up:

$ ps -Af
.
.
.
root ... su -s /bin/bash nobody my_command
nobody ... my_command

如果我杀死了根进程，没人进程仍然存在...但是有没有办法根本不运行根进程?由于获取my_command的ID并将其杀死会更加复杂.

And if I kill the root process, the nobody process still lives... but is there a way to not run the root process at all? Since getting the id of my_command and killing it is a bit more complicated.

推荐答案

这可以通过以下方式实现:

This could be achieved as:

su nobody -c "nohup my_command >/dev/null 2>&1 &"

，然后在pidFile中写入"my_command"的pid:

and to write the pid of 'my_command' in a pidFile:

pidFile=/var/run/myAppName.pid
touch $pidFile
chown nobody:nobody $pidFile
su nobody -c "nohup my_command >/dev/null 2>&1 & echo \$! > '$pidFile'"

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