更改文件编号Bash [英] Change file's numbers Bash

问题描述

我需要实现一个脚本(duplq.sh)，该脚本将使用命令行参数重命名当前目录中存在的所有文本文件.因此，如果执行命令 duplq.sh pic 0 3 ，它将进行以下转换:

I need to implement a script (duplq.sh) that would rename all the text files existing in the current directory using the command line arguments. So if the command duplq.sh pic 0 3 was executed, it would do the following transformation:

pic0.txt 必须重命名为 pic3.txt

pic1.txt 到 pic4.txt

pic2.txt 到 pic5.txt

pic3.txt 到 pic6.txt

等...

因此，第一个参数始终是文件名，第二个参数和第三个参数始终是正数.

So the first argument is always the name of a file the second and the third always a positive digit.

我还需要确保执行脚本时，第一次重命名(将pic0.txt更改为pic3.txt)不会删除当前目录中现有的pic3.txt文件.

I also need to make sure that when I execute my script, the first renaming (pic0.txt to pic3.txt), does not erase the existing pic3.txt file in the current directory.

这是我到目前为止所做的:

Here's what i did so far :

 #!/bin/bash

name="$1"
i="$2"
j="$3"


for file in $name*
do
    echo $file
    find /var/log -name 'name[$i]' | sed -e 's/$i/$j/g'
    i=$(($i+1))
    j=$(($j+1))
done 

但是find命令似乎不起作用.您还有其他解决方案吗?

But the find command does not seem to work. Do you have other solutions ?

推荐答案

查找可能的文件，按编号对名称进行 sort ，使用 sed 删除编号小于 $ 1 的文件，按编号反向 sort ，然后从顶部开始，从最高编号重命名为最低编号:

find possible files, sort the names by number, use sed to remove files with lower numbers than $1, reverse sort by number, and start at the top renaming from the highest number down to the lowest:

#!/bin/sh
find . -maxdepth 1 -type f -name "$1"'[0-9]*' | 
sort -g | sed -n "/^$1$2."'/,$p' | sort -gr | 
while read x ; do
    p="${x%%[0-9]*.*}"; s="${x##*[0-9]}" ; i="${x%$s}" i="${i#$p}"
    mv "$x" "$p$((i+$3))$s"
done 

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