Sed删除“."之后的所有内容.在文件中使用*命令? [英] Sed to remove everything after "." in file using * command?

问题描述

我有以下data.txt:

I have the following data.txt:

 95 flour.
 47 water.s
 etc..

我需要删除文件中句点(.)之后的所有内容，以产生如下内容:

I need to remove everything after the period (.) in the file to yield something like this:

 95 flour
 47 water
 etc..

我尝试使用以下sed命令没有成功，这会产生空白文档:

I have tried the using these sed commands without success, which yield a blank document:

sed "s/'.*//" data.txt > cleaned.txt 
sed 's/\.*//' data.txt > cleaned.txt 

推荐答案

要么使用反斜杠对.进行转义以获取文字.，或者使用方括号定义一个角色类别:

Either escape the . with a backslash to get a literal ., or use brackets to define a character class:

sed 's/\..*$//' data.txt > cleaned.txt
sed 's/[.].*$//' data.txt > cleaned.txt

您尝试了's/\.*//'，它是零个或多个文字点"，与后跟零个或多个字母的文字点"不同，即's/\..*//'.我还添加了一个 $ 以作好衡量.

You tried 's/\.*//', which is "zero or more literal dots", which is different from "literal dot followed by zero or more of anything", i.e. 's/\..*//'. I also added a $ for good measure.

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