如何使用Perl解释器对单引号进行转义? [英] How do I escape single quotes with perl interpreter?

问题描述

如何在bash表达式 find中转义单个qoutes.|xargs perl -pi -e's/'conflicts'=>"，//g'?我要在文件中替换字符串'conflicts'=>''吗?

How do I escape the single qoutes in my bash expression find . | xargs perl -pi -e 's/'conflicts' => '',//g'? I want to replace the string 'conflicts' => '', in my files?

推荐答案

您不能在单引号中直接将其转义，因此要获得单引号，您需要执行以下操作:

You can't directly escape it within single quotes, so to get a single quote you need to do something like:

$ echo 'i'\''m a string with a single quote'
i'm a string with a single quote

这结束了被引号的部分，转义了单引号，就像它在引号外一样，然后再次开始了引号.结果仍然是一个参数.

This ends the quoted part, escapes a single quote as it would appear outside of quotes, and then begins the quoting again. The result will still be one argument.

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