如何使用bash脚本和sed用换行符替换字符串? [英] How do I replace a string with a newline using a bash script and sed?

问题描述

我有以下输入内容:

Value1|Value2|Value3|Value4@@ Value5|Value6|Value7|Value8@@ Value9|etc...

在我的bash脚本中，我想用换行符替换 @@ .我曾用sed尝试过各种方法，但没有运气:

In my bash script I would like to replace the @@ with a newline. I have tried various things with sed but I'm not having any luck:

line=$(echo ${x} | sed -e $'s/@@ /\\\n/g')

最终，我需要将整个输入解析为行和值.也许我要去做错了.我打算用换行符替换 @@ ，然后通过设置 IFS ='|'来遍历输入，以拆分值.如果有更好的方法，请告诉我，我仍然是shell脚本的初学者.

Ultimately I need to parse this whole input into rows and values. Maybe I am going about it wrong. I was planning to replace the @@ with newlines and then loop through the input with setting IFS='|' to split up the values. If there is a better way please tell me, I am still a beginner with shell scripting.

推荐答案

这将起作用

sed 's/@@ /\n/g' filename

用新行替换 @@

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