计算文本文件中单词列表的出现次数 [英] Count occurrences of a list of words in a text file

问题描述

我有两个文本文件，File1看起来像这样:

I have two text files, File1 looks like this:

apple
dog
cat
..
..

和File2看起来像这样:

and File2 looks like this:

appledogtree 
dog
catapple
apple00001
..
..

我想计算File2中File1中单词列表的出现次数，并得到如下结果:

I want to count the occurrences of the list of words from File1 in File2, and get a result like below:

(文件1中的单词，文件2中的出现次数)

(words in File1, number of occurrences in File2)

apple 3
dog 2
cat 1

如何使用Bash命令行执行此操作?

How can I do this by using Bash command line?

推荐答案

您可以使用 fgrep 有效地做到这一点:

You can use fgrep to do this efficiently:

fgrep -of f1.txt f2.txt | sort | uniq -c | awk '{print $2 " " $1}'

给出以下输出:

apple 3
cat 1
dog 2

• fgrep -of f1.txt f2.txt 根据f1.txt中的模式提取f2.txt的所有匹配部分( -o 选项)
• sort |uniq -c 计算匹配模式
• 最后， awk 交换 uniq -c 输出中的单词顺序
• fgrep -of f1.txt f2.txt extracts all the matching parts (-o option) of f2.txt based on the patterns in f1.txt
• sort | uniq -c counts the matching patterns
• finally, awk swaps the order of words in uniq -c output

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