Bash:读入多个局部范围变量 [英] Bash: Read into multiple local scope variables

问题描述

根据此答案: https://stackoverflow.com/a/1952480/582917

我可以读入并因此分配多个变量.

I can read in and therefore assign multiple variables.

但是我希望这些变量在bash函数中是局部的，这样它才不会污染全局范围.

However I want those variables to be local to a bash function so it doesn't pollute the global scope.

有没有办法做类似的事情:

Is there a way to do something like:

func () {
    local read a b <<< $(echo 123 435)
    echo $a
}
func
echo $a

以上操作无效.读局部变量的好方法是什么?

The above doesn't work. What is a good way of reading into local variables?

推荐答案

您快到这里了:您只需要将变量定义为 local ，但是要预先在 read <中定义声明:

You were almost there: you just have to define the variables as local, but beforehand instead of in the read declaration:

func () {
     local a b
     read a b <<< $(echo 123 435)
     echo $a
}

测试

$ func 
123
$ echo $a
$

这篇关于Bash:读入多个局部范围变量的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！