在bash脚本中，如何循环浏览按日期排序的文件 [英] In a bash script how to loop through files sorted by date

问题描述

我有以下脚本:

#!/bin/sh
HOST='host'
USER='[e-mail]'
PASSWD='pwd'

for FILE in *.avi
do
    ftp -n $HOST <<END_SCRIPT
    quote USER $USER
    quote PASS $PASSWD
    binary
    put $FILE
    rm FILE 
    quit
done
END_SCRIPT
exit 0

如何确保首先处理最早的文件?我已经看到很多使用ls -t的技巧，但是必须有一种更简单的方法.

How do I ensure that I process the oldest file first? I have seen a lot of hacks that use ls -t, but there has to be a simpler way.

推荐答案

我将使用以下方法修改您的 for 循环:

I would modify your for loop with this:

for FILE in `ls -tU *.avi`
do
  #
  # loop content here with ${FILE}
  #
done

从 ls 文档中

-t      Sort by time modified (most recently modified first) before 
        sorting the operands by lexicographical order.
-U      Use time of file creation, instead of last modification for 
        sorting (-t) or long output (-l).

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