Bash完成以使"cd"命令从其他正在运行的shell中完成工作目录? [英] Bash completion to make 'cd' command complete working directories from other running shells?
问题描述
我正在尝试编写一个bash补全，以便让我可以补全其他shell所在的目录名称.
I'm trying to write a bash completion that will let me complete directory names that other shells are in.
例如，假设我在/very/long/path/name 中打开了另一个外壳，并且当前我所在的目录包含子目录 foo 和 bar .当我输入 cd< Tab> 时，我想查看:
For example, suppose I have another shell open in /very/long/path/name, and I'm currently in a directory that contains subdirs foo and bar. When I type cd <Tab>, I want to see:
$ cd <Tab>
foo/ bar/ /very/long/path/name
我有以下命令来生成可能完成的列表:
I have this command to produce the list of potential completions:
ps -Cbash -opid= | xargs pwdx | cut -d" " -f2 | sort -u | while read; do echo ${REPLY#$PWD/}; done | grep -v "^$"
为简便起见，我将其写为 ... pipeline ... .
For brevity, I'll write this as ...pipeline....
在我的系统上，有一个 _cd 函数可产生常规补全:
On my system there's a _cd function that produces the regular completion:
$ complete -p cd
complete -o nospace -F _cd cd
我想重用此 _cd 函数，因为它很简单(根据 type _cd 而言，大约30行代码).奖励指出解决方案是否可以重用已经定义的完成方式，无论它是否基于名为 _cd 的函数.
I would like to reuse this _cd function, because it's nontrivial (~30 lines of code, according to type _cd). Bonus points if the solution reuses whatever completion is already defined, whether or not it's based on a function called _cd.
我认为-完整的 -C 选项听起来很有希望，但我无法使其正常工作:
I thought the -C option to complete sounded promising, but I can't get it to work:
$ complete -C '...pipeline...' cd
$ cd <Tab>grep: cd: No such file or directory
grep: : No such file or directory
grep: cd: No such file or directory
为 -F 编写我自己的包装函数，将其附加到 COMPREPLY 数组，但效果也不佳:
Writing my own wrapper function for -F, which appends to the COMPREPLY array, also didn't quite work:
$ function _cd2() { _cd; COMPREPLY=( ${COMPREPLY[@]} $(...pipeline...) ); }
$ cd <Tab>
foo/ bar/ name/
它去除了除最后一个路径之外的所有路径分量.我认为这一定是由 _cd 设置的，但是我不确定如何抵消它.
It strips off all the path components except the last. I figure it must be something set up by _cd that does this, but I'm not sure how to counteract it.
如果我从 _cd2 中删除 _cd 调用，我会看到补全，但是它们不能正确补全部分目录名称.如果我键入 cd/ve< Tab> ，它仍然显示完整路径，而没有实际完成我的命令行.
If I remove the _cd call from _cd2, I do see the completions, but they don't properly complete partial directory names. If I type cd /ve<Tab>, it still shows the full path, without actually completing my command line.
我怎样才能做到这一点?
How can I get this to do what I want?
附录: _cd 的完整定义:
$ type _cd
_cd is a function
_cd ()
{
local cur prev words cword;
_init_completion || return;
local IFS='
' i j k;
compopt -o filenames;
if [[ -z "${CDPATH:-}" || "$cur" == ?(.)?(.)/* ]]; then
_filedir -d;
return 0;
fi;
local -r mark_dirs=$(_rl_enabled mark-directories && echo y);
local -r mark_symdirs=$(_rl_enabled mark-symlinked-directories && echo y);
for i in ${CDPATH//:/'
'};
do
k="${#COMPREPLY[@]}";
for j in $( compgen -d $i/$cur );
do
if [[ ( -n $mark_symdirs && -h $j || -n $mark_dirs && ! -h $j ) && ! -d ${j#$i/} ]]; then
j+="/";
fi;
COMPREPLY[k++]=${j#$i/};
done;
done;
_filedir -d;
if [[ ${#COMPREPLY[@]} -eq 1 ]]; then
i=${COMPREPLY[0]};
if [[ "$i" == "$cur" && $i != "*/" ]]; then
COMPREPLY[0]="${i}/";
fi;
fi;
return 0
}
推荐答案
您需要根据组合选项列表评估当前匹配项.这是一个说明运动部件的测试脚本:
You need to evaluate the current match against the list of combined options. Here's a test script that illustrates the moving parts:
#!/bin/bash
mkdir -p {my,other}/path/to/{a,b,c}
function _cd() {
COMPREPLY=( my/path/to/a my/path/to/b );
}
complete -o nospace -F _cd cd
function _cd2() {
local cur opts;
cur="${COMP_WORDS[COMP_CWORD]}";
_cd;
opts="${COMPREPLY[@]} other/path/to/c"; # here we combine options
COMPREPLY=($(compgen -W "${opts}" -- ${cur})); # here is the secret sauce
}
complete -F _cd2 cd
complete -p cd
最重要的一点是 _cd2 的 compgen 部分:该选项从组合的选项集中选择最合适的选项(在 $ opts ).
The most important points are in the compgen portion of _cd2: that chooses the most suitable options from the combined set of choices (in $opts).
这篇关于Bash完成以使"cd"命令从其他正在运行的shell中完成工作目录?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
