Bash while循环，如何读取输入直到条件为假 [英] Bash while loop, how to read input until a condition is false

问题描述

我一直遇到运行时错误.我正在OSX的终端上运行它.错误是

I keep getting a run time error. I'm running this in a terminal on OSX. The error is,

test.sh: line 15: while[!false]: command not found
test.sh: line 16: syntax error near unexpected token `do'
test.sh: line 16: `do'

由于我刚开始编写bash脚本，因此我无法弄清楚语法上哪里出了错.

I just can't figure where I've got wrong syntactically as I'm new to writing bash scripts.

ipa build &
TASK_PID=$!
sleep 5
kill $TASK_PID

finished=false
declare -a schemes

echo "*****************************************************************************************"
echo "| View the list of available build configs above."
echo "| Enter the name of the build you want,one at a time."
echo "| Type \"done\" to finish entering scheme names"
echo "*****************************************************************************************"

while[!${finished}]
do
read input
  if[$input == "done"]
  then
      finished=true
  else
  schemes=("${schemes[@]}" $input)
  echo ${schemes[0]}
  fi
done

echo "Do you want a verbose build? (y/n)"
read verbose


echo "Building your selected schemes....."
ipa build -s ${schemes[0]}

推荐答案

在测试条件下在方括号内留出空格

Give space around brackets in test conditions

while [ ! ${finished} ]

&

if [ $input = "done" ]

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