Shell Bash脚本以升序打印数字 [英] Shell Bash script to print numbers in ascending order

问题描述

我真的是Shell Bash脚本的新手.对于用户输入的给定任意数字，我需要在一行上按升序打印数字.

I am really new to shell Bash scripting. I need to print numbers in ascending order on a line for a given arbitrary number that is input by the user.

#!/bin/bash

declare nos[5]=(4 -1 2 66 10)
# Prints the number befor sorting

echo "Original Numbers in array:"
for (( i = 0; i <= 4; i++ ))
    do
      echo ${nos[$i]}
    done

 #
 # Now do the Sorting of numbers  
 #

for (( i = 0; i <= 4 ; i++ ))
do
   for (( j = $i; j <= 4; j++ ))
   do
      if [ ${nos[$i]} -gt ${nos[$j]}  ]; then
       t=${nos[$i]}
       nos[$i]=${nos[$j]}
       nos[$j]=$t
      fi
   done
done

#
# Print the sorted number
# 
echo -e "\nSorted Numbers in Ascending Order:"
for (( i=0; i <= 4; i++ )) 
do
  echo ${nos[$i]}
done

推荐答案

您可以使用以下脚本:

#!/bin/bash
IFS=' ' read -ra arr -p "Enter numbers: "
Enter numbers: 4 -1 2 66 10

sort -n <(printf "%s\n" "${arr[@]}")
-1
2
4
10
66

• IFS =''使 read 的所有数字都由空格分隔
• 'read -ra`读取数组中的所有数字
• sort -n 对数字进行数字排序
• printf％s \ n""$ {arr [@]}" 可以在单独的行中打印数组的每个元素
• <(printf％s \ n""$ {arr [@]}")是进程替换，使 printf 命令的行为类似于 sort -n 命令.
• IFS=' ' to make read all number delimited by space
• 'read -ra` to read all numbers in an array
• sort -n to sort numbers numerically
• printf "%s\n" "${arr[@]}" to print each element of array in separate line
• <(printf "%s\n" "${arr[@]}") is process substitution that make it printf command behave like a file for sort -n command.

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