bash-Shell脚本打开多个终端并执行不同的命令 [英] bash - Shell script opening multiple terminals and executing distinct commands

问题描述

我试图编写自己的shell脚本.到目前为止，由于'hold'选项，我已经设法打开了只能执行一个命令的4个xterminal.

I've tried to write my own shell script. So far I've managed to open 4 xterminals that can only execute ONE command because of the 'hold' option.

如果我不使用此选项，则终端将消失.

If i don't use this option, the terminals just disappear.

这是我的代码:

#!/bin/sh
xterm -title "App 1" -hold -e mycommand | mysecondcommand  &
xterm -title "App 2" -hold -e mycommand | mysecondcommand  &
xterm -title "App 3" -hold -e mycommand | mysecondcommand  &
xterm -title "App 4" -hold -e mycommand | mysecondcommand

不确定我是否应该在同一终端上执行第二条命令.

Not so sure if I'm supposed to execute the second command in the same terminal that way.

有什么想法吗?

谢谢

推荐答案

如果没有 -hold ，则xterm将在命令完成后立即关闭.您可以使用双引号和命令分隔符(例如; ，& )执行多个命令:

Without -hold, the xterm will close as soon as the command is completed. You can execute multiple commands by using double quotes and command separators (eg ;, &):

xterm -title "App 1" -e "mycommand; mysecondcommand" 

这篇关于bash-Shell脚本打开多个终端并执行不同的命令的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！