通过bash中的list传递带有空格的参数 [英] Passing arguments with spaces via list in bash

问题描述

在bash脚本中使用动态生成的参数调用某些函数很有趣.

I am interesting in calling some function using dynamically generated arguments in a bash script.

但是，如果某些参数中有空格，则似乎无效.

However, if some of the arguments had spaces, it does not seem to work.

让我们使用以下测试脚本:

Let's have this test script:

#!/bin/bash
# file uu.sh
[[ -z $1 ]] || echo '$1' $1
[[ -z $2 ]] || echo '$2' $2
[[ -z $3 ]] || echo '$3' $3
[[ -z $4 ]] || echo '$4' $4
[[ -z $5 ]] || echo '$5' $5
[[ -z $6 ]] || echo '$6' $6
[[ -z $7 ]] || echo '$7' $7
[[ -z $8 ]] || echo '$8' $8
[[ -z $9 ]] || echo '$9' $9
[[ -z $0 ]] || echo '$0' $0

任何我的脚本:

#!/bin/bash
# file vv.sh
ARR=(-x)
ARR+=($1)
ARR+=("$1")
ARR+=("'$1'")
ARR+=("\"$1\"")
bash uu.sh ${ARR[*]}
echo
bash uu.sh "${ARR[*]}"

当调用 bash vv.sh"a b" 时，我得到以下结果:

When calling bash vv.sh "a b" I get the following result:

$2 -x
$2 a
$3 b
$4 a
$5 b
$6 'a
$7 b'
$8 "a
$9 b"
$0 uu.sh

$1 -x a b a b 'a b' "a b"
$0 uu.sh

我期望一种将变量传递到uu.sh的方法，例如结果将是:

I am expecting a way to pass the variables to uu.sh such as the result would be:

$1 -x
$2 a b
$0 uu.sh

(我可以直接通过调用 bash uu.sh -xa \ b 或 bash uu.sh -x"ab" 或 bashuu.sh -x'a b')

(Which I can get directly by calling bash uu.sh -x a\ b, or bash uu.sh -x "a b", or bash uu.sh -x 'a b')

推荐答案

您应该具有这样的 vv.sh ，以便能够在 -x 之后传递所有参数.在 uu.sh 的第二个参数中:

You should have vv.sh like this to be able to pass all the arguments after -x in the 2nd argument to uu.sh:

#!/bin/bash
# file vv.sh
ARR=(-x)    # initialize array with "-x" as first element
ARR+=("$1") # append 1st argument in second element of array
bash uu.sh "${ARR[@]}" # call uu.sh with quoted and [@]

然后将其用作(请参见引用的参数):

Then use it as (see quoted arguments):

bash vv.sh "a b"

...将作为输出发出:

...which will emit as output:

$1 -x
$2 a b
$0 uu.sh

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